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Question

This question is based on the words given below.

(Left) BAD FIG ICE NOT (Right)

In each of the words, each vowel is changed to the letter immediately following it in the English alphabetical order and each consonant is changed to the letter immediately preceding in the English alphabetical order. In how many letter clusters thus formed, will no vowel appear?

The correct answer is
Two

Understanding the Letter Transformation

This problem involves transforming given words by applying specific rules to vowels and consonants based on their order in the English alphabet. The objective is to count how many of the resulting words, or 'letter clusters', contain no vowels.

The transformation rules are:

  • Each vowel (A, E, I, O, U) is replaced by the letter that comes immediately after it in the alphabet. For example, 'A' becomes 'B', 'E' becomes 'F'.
  • Each consonant is replaced by the letter that comes immediately before it in the alphabet. For example, 'B' becomes 'A', 'C' becomes 'B'.

We need to apply these rules to the words: BAD, FIG, ICE, and NOT.

Applying Transformation Rules to Each Word

Let's break down the transformation for each word:

Original WordTransformation ProcessTransformed WordVowels in Result?
BAD
  • B (Consonant) → Preceding letter = A
  • A (Vowel) → Following letter = B
  • D (Consonant) → Preceding letter = C
ABCYes (A)
FIG
  • F (Consonant) → Preceding letter = E
  • I (Vowel) → Following letter = J
  • G (Consonant) → Preceding letter = F
EJFYes (E)
ICE
  • I (Vowel) → Following letter = J
  • C (Consonant) → Preceding letter = B
  • E (Vowel) → Following letter = F
JBFNo
NOT
  • N (Consonant) → Preceding letter = M
  • O (Vowel) → Following letter = P
  • T (Consonant) → Preceding letter = S
MPSNo

Identifying Clusters Without Vowels

After performing the transformations, we examine the resulting words to see which ones contain only consonants:

  • ABC: Contains the vowel 'A'.
  • EJF: Contains the vowel 'E'.
  • JBF: Contains only consonants (J, B, F).
  • MPS: Contains only consonants (M, P, S).

We found two words, 'JBF' and 'MPS', that meet the condition of having no vowels.

Conclusion

The question asks for the number of letter clusters formed where no vowel appears. Our analysis shows that two such clusters were formed (JBF and MPS).

Comparing this result with the given options:

  • Two
  • None
  • Three
  • One

The count matches the option 'Two'.

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Important Questions from Alphabet or Word Test

  1. Select the correct option that shows the logical and meaningful sequence of the given words.

    i. flower

    ii. sprout

    iii. fruit

    iv. plant

    v. seed

  2. How many times consonants exceed vowels in the word, ‘ADVANCEMENT’?

  3. Which one of the following four addresses is NOT EXACTLY the same as the one given below?

    Steve Pipe 5Dick Collins Hall Redhill Street NW10

    (i) Steve Pipe 5Dick Collins Hall Redhill Streat NW10

    (ii) Steve Pipe 5Dick Collins Hall Redhill Street NW10

    (iii) Steve Pipe 5Dick Collins Hall Redhill Street NW10

    (iv) Steve Pipe 5Dick Collins Hall Redhill Street NW10

  4. The series given below contains a sequence of alphabets and numbers. Identify the incorrect combination:

    i. ytbei732btyei

    ii. ytbei732btyei

    iii. ytbe1732btyei

    iv. ytbei732btyei

  5. The series given below contains a sequence of alphabets and numbers. Identify the incorrect combination:

    i. huioi70110ihuoi

    ii. huioi70110ihuoi

    iii. huioi70110ihuoi

    iv. huioi70110ihooi

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