There is 70% increase in an amount in 7 years at simple interest. What will be the compound interest on ₹8,000 after 3 years at the same rate of interest?
This problem requires us to first determine the rate of simple interest from the given information and then use that rate to calculate the compound interest on a different amount over a different period.
We are told that an amount increases by 70% in 7 years at simple interest. This means the simple interest earned is 70% of the principal amount.
Let the principal amount be \(P\). The simple interest (\(SI\)) is 70% of \(P\), which is \(0.70 \times P\).
The time period (\(T\)) is 7 years.
The formula for simple interest is:
\(SI = \frac{P \times R \times T}{100}\)
Where \(R\) is the rate of interest per annum.
Substituting the known values:
\(0.70 \times P = \frac{P \times R \times 7}{100}\)
We can cancel \(P\) from both sides (assuming \(P > 0\)):
\(0.70 = \frac{R \times 7}{100}\)
Now, solve for \(R\):
\(0.70 \times 100 = R \times 7\)
\(70 = R \times 7\)
\(R = \frac{70}{7}\)
\(R = 10\%\)
So, the rate of simple interest is 10% per annum. This is the same rate we will use for the compound interest calculation.
Now we need to find the compound interest on ₹8,000 after 3 years at a rate of 10% per annum.
Principal amount (\(P\)) = ₹8,000
Rate of interest (\(R\)) = 10% per annum
Time period (\(n\)) = 3 years
The formula for the compound amount (\(A\)) is:
\(A = P \left(1 + \frac{R}{100}\right)^n\)
Substitute the values:
\(A = 8000 \left(1 + \frac{10}{100}\right)^3\)
\(A = 8000 \left(1 + 0.1\right)^3\)
\(A = 8000 \left(1.1\right)^3\)
Calculate \((1.1)^3\):
\(1.1 \times 1.1 = 1.21\)
\(1.21 \times 1.1 = 1.331\)
So,
\(A = 8000 \times 1.331\)
\(A = 10648\)
The compound amount after 3 years is ₹10,648.
The compound interest (\(CI\)) is the compound amount minus the principal:
\(CI = A - P\)
\(CI = 10648 - 8000\)
\(CI = 2648\)
The compound interest on ₹8,000 after 3 years at 10% per annum is ₹2,648.
First, we found the rate using the simple interest information, which was 10%. Then, we used this rate to calculate the compound interest on ₹8,000 for 3 years, finding it to be ₹2,648.
| Concept | Formula | Key Idea |
|---|---|---|
| Simple Interest (SI) | \(SI = \frac{P \times R \times T}{100}\) | Interest calculated only on the principal amount. |
| Compound Amount (A) | \(A = P \left(1 + \frac{R}{100}\right)^n\) | Principal plus interest compounded over time. |
| Compound Interest (CI) | \(CI = A - P\) or \(CI = P \left[\left(1 + \frac{R}{100}\right)^n - 1\right]\) | Interest calculated on the principal and accumulated interest from previous periods. |
Understanding the difference between simple interest and compound interest is crucial in finance and mathematics problems.
In this problem, the initial simple interest information helped us find the common rate, which was then applied in a compound interest scenario. The power of compounding becomes evident over longer periods or at higher rates.
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