We need to find the number of subgroups containing at least one Indian. A straightforward approach is to calculate the total possible subgroups and subtract the subgroups that contain *no* Indians.
The group has 6 people in total (3 Indians + 3 Chinese). The total number of possible subgroups (including the empty set) that can be formed from 6 people is given by $2^n$, where $n$ is the number of people.
Total subgroups = $2^6 = 64$.
Subgroups with no Indians must be formed exclusively from the Chinese members. There are 3 Chinese people.
The number of subgroups that can be formed using only the 3 Chinese people is $2^3$.
Subgroups with only Chinese members = $2^3 = 8$.
To find the number of subgroups with at least one Indian, we subtract the number of subgroups containing only Chinese people from the total number of subgroups.
Number of subgroups with at least one Indian = (Total subgroups) - (Subgroups with only Chinese members)
Number of subgroups with at least one Indian = $2^6 - 2^3 = 64 - 8 = 56$.
Therefore, there are 56 subgroups that include at least one Indian.
Three distinct sets of indistinguishable twins are to be seated at a circular table that has 8 identical chairs. Unique seating arrangements are defined by the relative positions of the people.
How many unique seating arrangements are possible such that each person is sitting next to their twin?
Two wizards try to create a spell using all the four elements, water, air, fire, and earth. For this, they decide to mix all these elements in all possible orders. They also decide to work independently. After trying all possible combination of elements, they conclude that the spell does not work.
How many attempts does each wizard make before coming to this conclusion, independently?