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Question

The work done on an object does not depend upon:

The correct answer is

Path followed

Understanding Work Done in Physics

Work done on an object is a measure of energy transfer that occurs when a force acts on the object over a displacement. In simple terms, work is done when a force causes an object to move. The amount of work done depends on several factors related to the force and the displacement.

Factors Affecting Work Done

The work done ($W$) by a constant force ($F$) on an object that undergoes a displacement ($d$) is given by the formula:

$$W = F \cdot d \cdot \cos(\theta)$$

Here, $\theta$ is the angle between the direction of the force vector and the direction of the displacement vector.

Let's analyze how work done depends on the factors listed in the options:

  • Displacement: The formula clearly includes the term $d$, which represents the magnitude of the displacement. If there is no displacement ($d=0$), the work done is zero, regardless of the force. Thus, work done depends on displacement.
  • Force applied: The formula includes the term $F$, which represents the magnitude of the force. If no force is applied ($F=0$), the work done is zero, even if there is displacement (which would require a force in the first place, but considering the equation inputs). Thus, work done depends on the force applied.
  • Angle between force and displacement: The formula includes the term $\cos(\theta)$, where $\theta$ is the angle between the force and displacement vectors. The value of $\cos(\theta)$ varies between -1 and 1 depending on the angle, affecting the work done. For example, if the force is perpendicular to the displacement ($\theta = 90^\circ$), $\cos(90^\circ) = 0$, and the work done is zero. If the force is in the same direction as displacement ($\theta = 0^\circ$), $\cos(0^\circ) = 1$, and work is maximum ($W=Fd$). If the force is opposite to displacement ($\theta = 180^\circ$), $\cos(180^\circ) = -1$, and work is negative ($W=-Fd$). Thus, work done depends on the angle between force and displacement.
  • Path followed: The formula for work ($W=Fd\cos\theta$) involves the force and the displacement, which is the straight-line distance between the initial and final positions. It does not inherently depend on the specific route or path taken by the object to get from the starting point to the ending point. For conservative forces (like gravity or the force from a spring), the work done depends only on the initial and final positions, making it completely independent of the path taken. While work done by non-conservative forces (like friction) can be path-dependent, the standard formula $W=Fd\cos\theta$ relates force and displacement, where displacement is a vector from the start to the end point, not the length of the path. Therefore, based on the fundamental definition and formula, work done depends on the force, the magnitude and direction of displacement, but not the detailed path followed.

Based on the analysis of the work done formula, the work done on an object depends on the force applied, the displacement, and the angle between them. It does not depend on the specific path taken by the object between its initial and final positions (especially in the context of displacement used in the work formula).

Conclusion

The work done on an object does not depend upon the path followed.

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Important Questions from Work

  1. A body of mass 100 kg rests on a horizontal plane, the value of coefficient of friction between the body and plane being 0.025. Find the work done in moving the body through a distance of 10 metres along the plane.

  2. A load of 16.5 kg is lifted through a height of 3.4 metres. Find the work done in kg metre.

  3. The energy equivalence of 1 eV is

  4. A body of mass 100 kg rests on a horizontal plane, the value of coefficient of friction between the body and plane being 0.025. Find the work done in moving the body through a distance of 10 metres along the plane.

  5. The work done by a person in carrying a box of mass 15 kg through a vertical height of 5 m is 5000 J. The mass of the person is _______ Take g = 10 m/s 2

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