The volume of a sphere of diameter 1 unit is ________ than the volume of a cube of side 1 unit.
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To determine how the volume of a sphere of diameter 1 unit compares to the volume of a cube of side 1 unit, we need to calculate the volume of each shape separately and then compare the results.
The formula for the volume of a sphere is given by:
$$V_s = \frac{4}{3} \pi r^3$$
Where \(V_s\) is the volume of the sphere and \(r\) is its radius.
Substituting the value of the radius into the formula:
$$V_s = \frac{4}{3} \pi \left(\frac{1}{2}\right)^3$$
$$V_s = \frac{4}{3} \pi \left(\frac{1}{8}\right)$$
$$V_s = \frac{4\pi}{24}$$
$$V_s = \frac{\pi}{6} \text{ cubic units}$$
To get an approximate numerical value, we can use the common approximation for \(\pi \approx 3.14159\):
$$V_s \approx \frac{3.14159}{6}$$
$$V_s \approx 0.5236 \text{ cubic units}$$
The formula for the volume of a cube is given by:
$$V_c = a^3$$
Where \(V_c\) is the volume of the cube and \(a\) is the length of its side.
Substituting the value of the side into the formula:
$$V_c = (1)^3$$
$$V_c = 1 \text{ cubic unit}$$
Now, let's compare the calculated volumes of the sphere and the cube:
Since \(0.5236 < 1\), it is clear that the volume of the sphere is numerically smaller than the volume of the cube.
| Shape | Given Dimensions | Volume Formula | Calculated Volume |
|---|---|---|---|
| Sphere | Diameter = 1 unit (Radius = 0.5 unit) | $V_s = \frac{4}{3} \pi r^3$ | $\frac{\pi}{6} \approx 0.5236$ cubic units |
| Cube | Side = 1 unit | $V_c = a^3$ | $1^3 = 1$ cubic unit |
Therefore, the volume of a sphere of diameter 1 unit is less than the volume of a cube of side 1 unit.
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