The void ratio of a soil is 0.25. Determin e the value of seepage velocity (vs) through the soi l if the discharge velocity is 3 × 10-4 mm/s.
15 × 10-4 mm/s
This question asks us to determine the seepage velocity through a soil given its void ratio and the discharge velocity. These are important concepts in soil mechanics related to the flow of water through soil pores.
In soil mechanics, there are two main velocities we consider for water flow:
The relationship between discharge velocity (\(v\)) and seepage velocity (\(v_s\)) is given by:
\(v_s = \frac{v}{n}\)
where \(n\) is the porosity of the soil.
Porosity (\(n\)) is defined as the ratio of the volume of voids (\(V_v\)) to the total volume (\(V\)) of the soil. Void ratio (\(e\)) is defined as the ratio of the volume of voids (\(V_v\)) to the volume of solids (\(V_s\)). The relationship between porosity and void ratio is:
\(n = \frac{e}{1+e}\)
We are given the void ratio \(e = 0.25\). We can calculate the porosity \(n\):
\(n = \frac{0.25}{1+0.25} = \frac{0.25}{1.25}\)
\(n = \frac{25/100}{125/100} = \frac{25}{125} = \frac{1}{5} = 0.2\)
So, the porosity of the soil is \(0.2\).
Now that we have the porosity (\(n = 0.2\)) and the discharge velocity (\(v = 3 \times 10^{-4}\) mm/s), we can calculate the seepage velocity (\(v_s\)) using the formula \(v_s = \frac{v}{n}\):
\(v_s = \frac{3 \times 10^{-4} \text{ mm/s}}{0.2}\)
\(v_s = \frac{3}{0.2} \times 10^{-4} \text{ mm/s}\)
\(v_s = \frac{30}{2} \times 10^{-4} \text{ mm/s}\)
\(v_s = 15 \times 10^{-4} \text{ mm/s}\)
The seepage velocity through the soil is \(15 \times 10^{-4}\) mm/s.
The calculated seepage velocity matches one of the given options.
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