The value of the expression \(\frac{1}{{1 + {{\log }_u}vw}} + \frac{1}{{1 + {{\log }_v}wu}} + \frac{1}{{1 + {{\log }_w}uv}}\)is ________.
1
To determine the value of the given mathematical expression, we will systematically simplify each of its terms by applying fundamental logarithm properties. The expression we need to evaluate is:
\[ \frac{1}{{1 + {{\log }_u}vw}} + \frac{1}{{1 + {{\log }_v}wu}} + \frac{1}{{1 + {{\log }_w}uv}} \]
The solution relies on the following essential logarithm properties:
Let's focus on the denominator of the first term:
\[ 1 + {{\log }_u}vw \]
Using the logarithm identity, we can rewrite \(1\) as \(\log_u u\). Substituting this into the denominator:
\[ \log_u u + {{\log }_u}vw \]
Now, apply the logarithm product rule \(\log_b M + \log_b N = \log_b (MN)\). Here, \(M=u\) and \(N=vw\):
\[ \log_u (u \cdot vw) = \log_u (uvw) \]
So, the first term of the expression becomes:
\[ \frac{1}{{\log_u (uvw)}} \]
Finally, applying the change of base formula \(\frac{1}{{\log_b a}} = \log_a b\), where \(b=u\) and \(a=uvw\), we get:
\[ \log_{uvw} u \]
We follow a similar process for the second term's denominator:
\[ 1 + {{\log }_v}wu \]
Replace \(1\) with \(\log_v v\) using the logarithm identity:
\[ \log_v v + {{\log }_v}wu \]
Apply the logarithm product rule \(\log_b M + \log_b N = \log_b (MN)\):
\[ \log_v (v \cdot wu) = \log_v (uvw) \]
Thus, the second term of the expression is:
\[ \frac{1}{{\log_v (uvw)}} \]
Using the change of base formula \(\frac{1}{{\log_b a}} = \log_a b\), where \(b=v\) and \(a=uvw\), we obtain:
\[ \log_{uvw} v \]
And for the third term's denominator:
\[ 1 + {{\log }_w}uv \]
Substitute \(1\) with \(\log_w w\) using the logarithm identity:
\[ \log_w w + {{\log }_w}uv \]
Apply the logarithm product rule \(\log_b M + \log_b N = \log_b (MN)\):
\[ \log_w (w \cdot uv) = \log_w (uvw) \]
Therefore, the third term of the expression is:
\[ \frac{1}{{\log_w (uvw)}} \]
Applying the change of base formula \(\frac{1}{{\log_b a}} = \log_a b\), where \(b=w\) and \(a=uvw\), we get:
\[ \log_{uvw} w \]
Now, we substitute these simplified forms back into the original expression:
\[ \log_{uvw} u + \log_{uvw} v + \log_{uvw} w \]
Since all terms now have the same base, \(uvw\), we can apply the logarithm product rule multiple times:
\[ \log_{uvw} (u \cdot v \cdot w) \]
This simplifies to:
\[ \log_{uvw} (uvw) \]
Finally, using the logarithm identity \(\log_b b = 1\), where the base and the argument of the logarithm are identical (in this case, both are \(uvw\)), we conclude:
\[ \log_{uvw} (uvw) = 1 \]
Thus, the value of the given logarithm expression is 1.
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