The value of \(\frac{2 \sin^2 30° \tan 60°-3 \cos^2 60° \sec^2 30°}{4\cot^2 45°-\sec^2 60°+ \sin^2 60°+\cos^2 90°}\) is
To find the value of the given trigonometric expression, we need to substitute the standard trigonometric values for the angles 30°, 60°, 45°, and 90°. Let's list the required standard values:
| Trigonometric Ratio | 30° | 45° | 60° | 90° |
|---|---|---|---|---|
| sin | \(\frac{1}{2}\) | \(\frac{1}{\sqrt{2}}\) | \(\frac{\sqrt{3}}{2}\) | 1 |
| cos | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{\sqrt{2}}\) | \(\frac{1}{2}\) | 0 |
| tan | \(\frac{1}{\sqrt{3}}\) | 1 | \(\sqrt{3}\) | Undefined |
| cot | \(\sqrt{3}\) | 1 | \(\frac{1}{\sqrt{3}}\) | 0 |
| sec | \(\frac{2}{\sqrt{3}}\) | \(\sqrt{2}\) | 2 | Undefined |
| cosec | 2 | \(\sqrt{2}\) | \(\frac{2}{\sqrt{3}}\) | 1 |
The given expression is:
\(\frac{2 \sin^2 30° \tan 60°-3 \cos^2 60° \sec^2 30°}{4\cot^2 45°-\sec^2 60°+ \sin^2 60°+\cos^2 90°}\)
The numerator is \(2 \sin^2 30° \tan 60°-3 \cos^2 60° \sec^2 30°\). Substitute the standard values:
Substituting these values into the numerator:
\(2 \left(\frac{1}{2}\right)^2 (\sqrt{3}) - 3 \left(\frac{1}{2}\right)^2 \left(\frac{2}{\sqrt{3}}\right)^2\)
Calculate the squares:
\(2 \left(\frac{1}{4}\right) (\sqrt{3}) - 3 \left(\frac{1}{4}\right) \left(\frac{4}{3}\right)\)
Simplify the terms:
\(\frac{2\sqrt{3}}{4} - 3 \left(\frac{4}{12}\right)\)
\(\frac{\sqrt{3}}{2} - 3 \left(\frac{1}{3}\right)\)
\(\frac{\sqrt{3}}{2} - 1\)
Combine into a single fraction:
\(\frac{\sqrt{3} - 2}{2}\)
So, the numerator evaluates to \(\frac{\sqrt{3} - 2}{2}\).
The denominator is \(4\cot^2 45°-\sec^2 60°+ \sin^2 60°+\cos^2 90°\). Substitute the standard values:
Substituting these values into the denominator:
\(4(1)^2 - (2)^2 + \left(\frac{\sqrt{3}}{2}\right)^2 + (0)^2\)
Calculate the squares:
\(4(1) - 4 + \frac{3}{4} + 0\)
Simplify the terms:
\(4 - 4 + \frac{3}{4} + 0\)
\(0 + \frac{3}{4}\)
\(\frac{3}{4}\)
So, the denominator evaluates to \(\frac{3}{4}\).
Now, divide the numerator by the denominator:
Value of expression = \(\frac{\text{Numerator}}{\text{Denominator}} = \frac{\frac{\sqrt{3} - 2}{2}}{\frac{3}{4}}\)
To divide by a fraction, multiply by its reciprocal:
\(\frac{\sqrt{3} - 2}{2} \times \frac{4}{3}\)
Multiply the fractions:
\(\frac{(\sqrt{3} - 2) \times 4}{2 \times 3}\)
\(\frac{4(\sqrt{3} - 2)}{6}\)
Simplify the fraction by dividing the numerator and denominator by 2:
\(\frac{2(\sqrt{3} - 2)}{3}\)
This is the final value of the expression.
Let's compare the calculated value \(\frac{2(\sqrt{3} - 2)}{3}\) with the given options:
The calculated value matches option 3.
| Angle (\(\theta\)) | \(\sin \theta\) | \(\cos \theta\) | \(\tan \theta\) | \(\cot \theta\) | \(\sec \theta\) | \(\csc \theta\) |
|---|---|---|---|---|---|---|
| 0° | 0 | 1 | 0 | Undefined | 1 | Undefined |
| 30° (\(\frac{\pi}{6}\)) | \(\frac{1}{2}\) | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{\sqrt{3}}\) | \(\sqrt{3}\) | \(\frac{2}{\sqrt{3}}\) | 2 |
| 45° (\(\frac{\pi}{4}\)) | \(\frac{1}{\sqrt{2}}\) | \(\frac{1}{\sqrt{2}}\) | 1 | 1 | \(\sqrt{2}\) | \(\sqrt{2}\) |
| 60° (\(\frac{\pi}{3}\)) | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{2}\) | \(\sqrt{3}\) | \(\frac{1}{\sqrt{3}}\) | 2 | \(\frac{2}{\sqrt{3}}\) |
| 90° (\(\frac{\pi}{2}\)) | 1 | 0 | Undefined | 0 | Undefined | 1 |
This problem relies on understanding standard trigonometric values. It's also useful to remember fundamental trigonometric identities that can simplify expressions:
These identities help in simplifying complex trigonometric expressions, although the problem here mainly required knowing the values at specific angles.
If sec 4θ = cosec (θ + 20°), then θ is equal to:
The value of sin 260° cos 245° + 2 tan 260° - cosec 230° is equal to:
Find the value of sin 4 30° + cos 4 30° - sin 25° cos 65° - sin 65° cos25°.
Find the value of cot 25°cot 35°cot 45°cot 55°cot 65°.