The value of (cos2 1° + cos2 5° + cos2 9° + ... + cos2 81° + cos2 85° + cos2 89°) is
The problem asks us to find the sum of a series involving cosine squared terms: \( \cos^2 1^\circ + \cos^2 5^\circ + \cos^2 9^\circ + \dots + \cos^2 81^\circ + \cos^2 85^\circ + \cos^2 89^\circ \). To solve this cos series, we need to analyze the pattern of the angles and apply relevant trigonometric identities.
Let's examine the angles in the given cos series: \(1^\circ, 5^\circ, 9^\circ, \dots, 81^\circ, 85^\circ, 89^\circ\).
We can observe that the difference between consecutive terms is constant:
This confirms that the angles form an arithmetic progression with a common difference \(d = 4^\circ\). The last term in this arithmetic progression is \(a_n = 89^\circ\).
To find the total number of terms (\(n\)) in the cos series, we use the formula for the n-th term of an arithmetic progression:
\(a_n = a_1 + (n-1)d\)
Substituting the values:
\(89^\circ = 1^\circ + (n-1)4^\circ\)
\(88^\circ = (n-1)4^\circ\)
\(22 = n-1\)
\(n = 23\)
Therefore, there are 23 terms in the given cos series.
We will use the following fundamental trigonometric identities to simplify the sum of the cos series:
Combining these, we can write:
\( \cos^2 \theta + \cos^2 (90^\circ - \theta) = \cos^2 \theta + \sin^2 \theta = 1 \)
This identity is crucial for pairing the terms in our cos series.
Since there are 23 terms, which is an odd number, there will be one middle term that does not have a pair. The middle term is the \(\left(\frac{n+1}{2}\right)\)-th term, which is the \(\left(\frac{23+1}{2}\right)\)-th = 12th term.
Let's find the 12th term in the arithmetic progression of angles:
\(a_{12} = a_1 + (12-1)d = 1^\circ + 11 \times 4^\circ = 1^\circ + 44^\circ = 45^\circ\)
So, the middle term is \( \cos^2 45^\circ \).
Now, let's pair the terms from the beginning and the end of the cos series using the identity \( \cos^2 \theta + \cos^2 (90^\circ - \theta) = 1 \):
| Pair | Sum | Calculation |
|---|---|---|
| \( \cos^2 1^\circ + \cos^2 89^\circ \) | 1 | \( \cos^2 1^\circ + \cos^2 (90^\circ - 1^\circ) = \cos^2 1^\circ + \sin^2 1^\circ = 1 \) |
| \( \cos^2 5^\circ + \cos^2 85^\circ \) | 1 | \( \cos^2 5^\circ + \cos^2 (90^\circ - 5^\circ) = \cos^2 5^\circ + \sin^2 5^\circ = 1 \) |
| \( \cos^2 9^\circ + \cos^2 81^\circ \) | 1 | \( \cos^2 9^\circ + \cos^2 (90^\circ - 9^\circ) = \cos^2 9^\circ + \sin^2 9^\circ = 1 \) |
| ... | ... | ... |
| \( \cos^2 41^\circ + \cos^2 49^\circ \) | 1 | \( \cos^2 41^\circ + \cos^2 (90^\circ - 41^\circ) = \cos^2 41^\circ + \sin^2 41^\circ = 1 \) |
Since there are 23 terms and one middle term (\( \cos^2 45^\circ \)), the remaining \(23-1=22\) terms form \(\frac{22}{2} = 11\) pairs. Each of these 11 pairs sums to 1.
So, the sum of these 11 pairs is \(11 \times 1 = 11\).
The value of \( \cos 45^\circ \) is \( \frac{1}{\sqrt{2}} \).
Therefore, the middle term \( \cos^2 45^\circ \) is:
\( \cos^2 45^\circ = \left(\frac{1}{\sqrt{2}}\right)^2 = \frac{1}{2} \)
The total sum of the cos series is the sum of the paired terms plus the middle term:
Total Sum = (Sum of 11 pairs) + (Value of middle term)
Total Sum = \(11 + \frac{1}{2}\)
Total Sum = \(11\frac{1}{2}\)
Thus, the value of the given cos series is \(11\frac{1}{2}\).
If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.
1 + tan 15° cot 75° is equal to:
The value of cot (-315°) is :
θ = 135°; γ = 15°.
What is the value of 2 cos(θ) sin(γ)?
If tan(90 – θ) = \(\frac{2}{\sqrt3}\), then the value of \(2\sqrt3\) tan θ + 1 is: