Question
The value of (4096/9) -(3/2) × (4/3)3 ÷ 4√(256)-3 is:
The correct answer is
1⁄64
\((4096/9)^{-3/2}\times(4/3)^3\div(\sqrt[4]{256})^{-3}=\frac{27}{262144}\frac{64}{27}(64)=\frac1{64}\)
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