The total rainfall in a catchment area 1200 km2 during a 6 hours storm is 16 cm. While the surface run-off due to storm is 1.2 × 108 m3. The φ index is
1.0 cm/hr
The $\phi$-index is a crucial concept in hydrology used to estimate the average rate of infiltration above which the rainfall becomes surface runoff. It represents the average rainfall intensity above which rainfall excess occurs over a given area and duration.
To calculate the $\phi$-index, we need the total rainfall, the resulting surface runoff, and the storm duration. The difference between the total rainfall and the surface runoff represents the total losses, primarily due to infiltration, evaporation, and initial abstraction, assumed to be uniform throughout the storm above the $\phi$-index rate.
The formula for $\phi$-index is given by:
$\phi\text{-index} = \frac{\text{Total Rainfall Depth} - \text{Runoff Depth}}{\text{Storm Duration}}$
First, we need to ensure all measurements are in consistent units. The surface runoff is given in volume (m³) and the area in km². We will convert the runoff volume into an equivalent depth over the catchment area, expressed in centimeters, to match the total rainfall unit.
1 km = 1000 m
1 km² = $(1000 \text{ m})^2 = 10^6$ m²
Catchment Area (A) = 1200 km² = $1200 \times 10^6$ m² = $1.2 \times 10^9$ m²
Runoff Depth (R) is the volume of runoff spread over the catchment area.
Runoff Depth = $\frac{\text{Runoff Volume}}{\text{Catchment Area}}$
R = $\frac{1.2 \times 10^8 \text{ m}^3}{1.2 \times 10^9 \text{ m}^2} = 0.1$ m
1 m = 100 cm
R = $0.1 \text{ m} \times 100 \text{ cm/m} = 10$ cm
Total losses represent the portion of rainfall that did not become surface runoff.
Total Losses = Total Rainfall Depth - Runoff Depth
Total Losses = 16 cm - 10 cm = 6 cm
Now, we use the formula for the $\phi$-index.
Storm Duration (t) = 6 hours
$\phi\text{-index} = \frac{\text{Total Losses}}{\text{Storm Duration}}$
$\phi\text{-index} = \frac{6 \text{ cm}}{6 \text{ hours}} = 1.0 \text{ cm/hr}$
We calculated the runoff depth from the given runoff volume and catchment area. Then, we subtracted this runoff depth from the total rainfall depth to find the total losses during the storm. Finally, we divided the total losses by the storm duration to determine the $\phi$-index.
| Parameter | Value | Units |
|---|---|---|
| Catchment Area (A) | $1.2 \times 10^9$ | m² |
| Runoff Volume (V) | $1.2 \times 10^8$ | m³ |
| Runoff Depth (R) | 10 | cm |
| Total Rainfall (P) | 16 | cm |
| Storm Duration (t) | 6 | hours |
| Total Losses | 6 | cm |
| Phi Index ($\phi$) | 1.0 | cm/hr |
The calculated $\phi$-index is 1.0 cm/hr. This means that, on average, 1.0 cm/hr of rainfall intensity was lost to infiltration and other abstractions during the 6-hour storm before runoff began or while it was occurring. Any rainfall intensity above this rate contributed to the surface runoff.
Reviewing the essential formulas and conversions helps in solving hydrology problems like calculating the $\phi$-index.
| Concept | Formula/Conversion |
|---|---|
| Area Conversion (km² to m²) | 1 km² = $10^6$ m² |
| Runoff Depth (from Volume & Area) | Depth = Volume / Area |
| Length Conversion (m to cm) | 1 m = 100 cm |
| Total Losses | Total Rainfall - Runoff Depth |
| Phi Index ($\phi$) | (Total Rainfall - Runoff Depth) / Storm Duration |
Understanding the relationship between rainfall and runoff is fundamental in hydrology. Not all rainfall becomes runoff; a significant portion is lost due to various processes collectively known as abstractions. The $\phi$-index is a simplified way to account for these losses.
The $\phi$-index method assumes a constant loss rate throughout the duration when rainfall intensity exceeds this rate. While a simplification, it is widely used for practical hydrological calculations, especially when detailed infiltration data is unavailable. The calculated $\phi$-index of 1.0 cm/hr for this specific storm provides insight into the average loss rate experienced by the catchment area during the 6-hour storm event.
Isohyet is a line joining points having
Which of the following is a non-recording rain gauge?
In Symons rain gauge, the rim of the collector is set in a horizontal plane at a height of ________ above the ground level.
Which rain gauge is NOT able to gives a plot of a mass curve of rainfall?