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Question

A fabric is woven from 38 tex yarns of 0.65 packing coefficient and 1.54 g/cm$^3$ fibre density. The fabric has 30 ends per cm and 25 picks per cm. Assume that warp is jammed.

The thickness of the above fabric (mm) is approximately

The correct answer is
0.5

Fabric Thickness Calculation

This solution calculates the approximate thickness of a fabric based on its yarn properties and construction details.

Yarn Diameter Calculation

First, we determine the effective diameter of the yarn using the given tex value, fibre density, and packing coefficient.

  • Given:
    • Tex ($T_x$) = 38 g/km
    • Fibre Density ($\rho_f$) = 1.54 g/cm$^3$
    • Yarn Packing Coefficient ($k$) = 0.65
  • Step 1: Calculate yarn volume per meter.
    • Mass per meter = $38 \text{ g/km} \times 1 \text{ km} / 1000 \text{ m} = 0.038$ g/m.
    • Volume per meter = Mass / Density = $\frac{0.038 \text{ g}}{1.54 \text{ g/cm}^3} \approx 0.024675 \text{ cm}^3$/m.
  • Step 2: Calculate yarn cross-sectional area.
    • Area per meter = Volume per meter / Length = $\frac{0.024675 \text{ cm}^3}{100 \text{ cm}} = 0.00024675 \text{ cm}^2$.
  • Step 3: Calculate yarn diameter ($d_{yarn}$).
    • Assume yarn cross-section area $A = \pi r^2$.
    • $r^2 = \frac{A}{\pi} = \frac{0.00024675 \text{ cm}^2}{\pi} \approx 0.00007854 \text{ cm}^2$.
    • Radius $r = \sqrt{0.00007854} \approx 0.00886 \text{ cm} = 0.0886 \text{ mm}$.
    • Yarn diameter $d_{yarn} = 2r \approx 2 \times 0.0886 \text{ mm} = 0.177 \text{ mm}$.

Fabric Thickness Estimation

The fabric thickness depends on the yarn diameter and how the yarns are packed. The condition "warp is jammed" suggests the warp yarns are tightly packed, significantly influencing the thickness.

  • Given:
    • Ends per cm ($N_e$) = 30
    • Picks per cm ($N_p$) = 25
    • Calculated yarn diameter ($d_{yarn}$) $\approx 0.177$ mm
  • Step 4: Estimate fabric thickness ($T$).
    • Fabric thickness is often related to yarn diameter. A common approximation, especially when yarns are tightly packed (like a jammed warp), suggests $T$ can be approximately $2.5$ to $3$ times the yarn diameter.
    • Using the approximation $T \approx 3 \times d_{yarn}$:
    • $T \approx 3 \times 0.177 \text{ mm} \approx 0.531 \text{ mm}$.
  • Step 5: Compare with options.
    • The calculated thickness $T \approx 0.531$ mm is approximately 0.5 mm.

Therefore, the approximate thickness of the fabric is 0.5 mm.

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Important Questions from FABR Fabric Geometry Fabric Cover Factor

  1. A woven fabric has weft yarn of 24 tex and pick density of 25 per cm. It is desired to replace only the weft with a 6 tex yarn of same packing density. The pick density per cm required to keep the fabric cover same (answer in integer) is ________.
  2. A series of plain knitted fabrics has varying stitch length ($\ell $). The fabrics are composed of cotton yarns having same packing density but differing in linear density ($T$). The ratio between tightness factor and areal density of the fabrics is proportional to

  3. For a given woven fabric, fractional cover is 0.5 for both warp and weft. The fractional cover of the fabric, (rounded off to two decimal places), is____.

  4. Cloth cover factor of a square plain jammed cotton fabric, accurate to one decimal place, is________.

  5. A plain woven fabric with 20 ends per cm and 30 picks per cm is prepared with 30 tex warp yarns and 25 tex weft yarns. Neglecting yarn crimp, the areal density ($g/m^2$) of the fabric (in integer) is ________.
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