All Exams Test series for 1 year @ ₹349 only
Question

The sum of the series 31 + 33 +.......+ 53 is

The correct answer is

504

Given:

The series 31 + 33 +...........+ 53 is an arithmetic series.

Concept:

The nth term of an arithmetic series, an = a1 + (n - 1)d

The sum of the series, Sn = n/2[2a1 + (n-1)d]

Calculation:

⇒ Let the first term of the arithmetic series, a1 = 31

⇒ The second term of the arithmetic series, a2 = 33

And the common difference d, d = a2 - a1 = 33 - 31 = 2

⇒ Therefore, d = 2

⇒ The nth term of the arithmetic series, an = a1 + (n - 1)d

⇒ 53 = 31 + (n - 1)(2)

⇒ 53 - 31 = 2n - 2

⇒ 22 = 2n - 2

⇒ 22 + 2 = 2n

⇒ 2n = 24

⇒ n = 24/2

⇒ n = 12

⇒ Therefore, 53 is the 12th term of the arithmetic series.

⇒ The sum of the series is, Sn = n/2[2a1 + (n - 1)d]

⇒ S12 = (12/2)[2 × 31 + (12 - 1)2]

⇒ 12 × (2/2) [31 + 11]

⇒ 12(42)

⇒ 504

Thus, the sum of the series 31 + 33 +......+ 53 is 504.

Was this answer helpful?

Important Questions from Geometric Progressions

  1. If \(2^{\frac{1}{c}}, 2^{\frac{b}{a c}}, 2^{\frac{1}{a}}\) are in GP, then which one of the following is correct ?

  2. If G is the geometric mean of numbers 1, 2, 22, 23,.....2n-1, then what is the value of 1 + 2log2G ?

  3. If m is the geometric mean of \({\left( {\frac{{\rm{y}}}{{\rm{z}}}} \right)^{\log \left( {{\rm{yz}}} \right)}},{\rm{\;}}{\left( {\frac{{\rm{z}}}{{\rm{x}}}} \right)^{\log \left( {{\rm{zx}}} \right)}}{\rm{\;and\;}}{\left( {\frac{{\rm{x}}}{{\rm{y}}}} \right)^{\log \left( {{\rm{xy}}} \right)}}\) then what is the value of m?

  4. The value of the infinite product \({6^{\frac{1}{2}}} \times {6^{\frac{1}{2}}} \times {6^{\frac{3}{8}}} \times {6^{\frac{1}{4}}} \times \ldots \) is

  5. The geometric mean of the observations x 1, x 2, x 3, … x nis G 1. The geometric mean of the observations y 1, y 2, y 3,… y nis G 2. The geometric mean of observations \(\frac{{{{\rm{x}}_1}}}{{{{\rm{y}}_1}}},\frac{{{{\rm{x}}_2}}}{{{{\rm{y}}_2}}},\frac{{{{\rm{x}}_3}}}{{{{\rm{y}}_3}}}, \ldots \frac{{{{\rm{x}}_{\rm{n}}}}}{{{{\rm{y}}_{\rm{n}}}}}\) is

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App