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Question

The state of stress at a point in a 2-D loading is such that the Mohr's circle is a point located at 175 MPa on the positive normal stress axis. The maximum and minimum principal stresses respectively, from Mohr's circle, are:

The correct answer is

+175 MPa; +175 MPa

Understanding Mohr's Circle as a Point

Mohr's circle is a graphical representation used in mechanics of materials to illustrate the state of stress at a specific point within a material. It plots normal stress ($\sigma$) on the horizontal axis and shear stress ($\tau$) on the vertical axis. The principal stresses, which are the maximum and minimum normal stresses experienced at that point, are found where the circle intersects the horizontal normal stress axis.

Interpreting a Point Mohr's Circle

In this specific problem, the Mohr's circle is described as a single point located at 175 MPa on the positive normal stress axis. This indicates a very specific and simple stress state:

  • Radius is Zero: When the Mohr's circle is just a point, it signifies that the radius of the circle is zero. The radius of Mohr's circle is related to the shear stresses and the difference between normal stresses. A zero radius implies that the shear stresses ($\tau_{xy}$) are zero, and the normal stresses on the perpendicular planes are equal ($\sigma_x = \sigma_y$).
  • Center Location: The location of this single point on the normal stress axis represents the center of the Mohr's circle. The center's coordinate on the normal stress axis is given by the average normal stress, $\sigma_{avg} = \frac{\sigma_x + \sigma_y}{2}$.

Calculating Principal Stresses

Given that the Mohr's circle is a point at 175 MPa on the normal stress axis:

  • The center of the circle is at $\sigma_{avg} = 175$ MPa.
  • The radius of the circle is $R = 0$ MPa.

The principal stresses ($\sigma_1$ and $\sigma_2$) are calculated using the formulas:

$$ \sigma_1 = \sigma_{avg} + R $$ $$ \sigma_2 = \sigma_{avg} - R $$

Substituting the values:

$$ \sigma_1 = 175 \text{ MPa} + 0 \text{ MPa} = 175 \text{ MPa} $$ $$ \sigma_2 = 175 \text{ MPa} - 0 \text{ MPa} = 175 \text{ MPa} $$

This means that at this point, the stress is hydrostatic (equal in all directions in the 2D plane), with both the maximum and minimum principal stresses being 175 MPa.

Conclusion

Therefore, the maximum and minimum principal stresses, derived from a Mohr's circle that is a single point at 175 MPa on the normal stress axis, are both +175 MPa.

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Important Questions from Principle Stress

  1. A shaft subjected to torsion experiences a pure shear stress τ on the surface. The maximum principal stress on the surface which is at 45° to the axis will have a value

  2. A solid circular shaft of diameter 100 mm is subjected to an axial stress of 50 MPa. It is further subjected to a torque of 10 kNm. The maximum principal stress experienced on the shaft is closest to

  3. The diagonal elements of a 3D matrix containing normal stresses and shear stresses are 50, 60 and 80. Find the first stress invariant of the matrix.

  4. The relation between maximum shear stress (τm) and maximum normal stress (σm ) in an axially loaded rectangular bar is:

  5. Analytical and graphical methods are used for finding the ________ on an oblique section.

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