The speed of a boat in still water is 30 km/h and the speed of the seam is 7.5 km/h. What is the time in hours taken by the boat in the stream to go from point A to B and then back to A covering a total distance of 90 km?
3.2
This question involves the concepts of boat speed in still water and the speed of the stream. When a boat moves in a stream, its effective speed changes depending on whether it is moving in the same direction as the stream (downstream) or against the direction of the stream (upstream).
When the boat travels downstream, the speed of the stream adds to the boat's speed in still water, making it faster. When it travels upstream, the speed of the stream opposes the boat's motion, making it slower.
Let \(V_b\) be the speed of the boat in still water and \(V_s\) be the speed of the stream.
Given:
Calculating the speeds:
The boat travels from point A to B and then back to A, covering a total distance of 90 km. This means the distance from A to B (one way) is half of the total distance.
Total distance = 90 km (A to B and B to A)
Distance from A to B = Distance from B to A = \(\frac{90 \text{ km}}{2} = 45 \text{ km}\)
The formula for time is:
\(\text{Time} = \frac{\text{Distance}}{\text{Speed}}\)
We need to calculate the time taken for the downstream journey (say, A to B) and the time taken for the upstream journey (B to A).
Let's calculate \(T_d\):
\(T_d = \frac{45}{37.5} = \frac{450}{375}\)
Dividing both numerator and denominator by 75:
\(450 \div 75 = 6\)
\(375 \div 75 = 5\)
So, \(T_d = \frac{6}{5} = 1.2 \text{ hours}\)
Let's calculate \(T_u\):
\(T_u = \frac{45}{22.5} = \frac{450}{225}\)
Dividing both numerator and denominator by 225:
\(450 \div 225 = 2\)
\(225 \div 225 = 1\)
So, \(T_u = \frac{2}{1} = 2 \text{ hours}\)
The total time taken for the round trip from A to B and back to A is the sum of the time taken for the downstream journey and the time taken for the upstream journey.
\(\text{Total Time} (T_{\text{total}}) = T_d + T_u\)
\(T_{\text{total}} = 1.2 \text{ hours} + 2 \text{ hours}\)
\(T_{\text{total}} = 3.2 \text{ hours}\)
The total time taken by the boat to cover a total distance of 90 km (A to B and back to A) is 3.2 hours.
| Parameter | Value |
|---|---|
| Speed of boat in still water | 30 km/h |
| Speed of stream | 7.5 km/h |
| Downstream Speed (30 + 7.5) | 37.5 km/h |
| Upstream Speed (30 - 7.5) | 22.5 km/h |
| Total Distance (A to B and back) | 90 km |
| Distance one way (A to B or B to A) | 45 km |
| Time Downstream (45 / 37.5) | 1.2 hours |
| Time Upstream (45 / 22.5) | 2 hours |
| Total Time (1.2 + 2) | 3.2 hours |
The final answer is 3.2 hours.
| Concept | Formula | Description |
|---|---|---|
| Downstream Speed | \(V_d = V_b + V_s\) | Boat speed is helped by the stream speed. |
| Upstream Speed | \(V_u = V_b - V_s\) | Boat speed is opposed by the stream speed. |
| Time taken | \(T = \frac{D}{S}\) | Distance divided by speed. |
| Speed of boat in still water | \(V_b = \frac{V_d + V_u}{2}\) | Average of downstream and upstream speeds. |
| Speed of stream | \(V_s = \frac{V_d - V_u}{2}\) | Half of the difference between downstream and upstream speeds. |
Problems involving boat and stream speed are a specific type of distance, speed, and time problem. The key is to correctly identify the effective speed of the object (boat, swimmer, etc.) relative to the ground when influenced by a moving medium (stream, wind, etc.).
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