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Question

The slope of the line 4x + 3y - 4 = 0 is:

The correct answer is \(-\frac{4}{3}\)

Finding the Slope of a Line from its Equation

The slope of a line is a measure of its steepness and direction. For a linear equation given in the standard form \(Ax + By + C = 0\), there is a simple formula to determine its slope.

Understanding the Standard Form and Slope

A linear equation in two variables, x and y, can be written in the standard form:

\(Ax + By + C = 0\)

where A, B, and C are constants, and A and B are not both zero. The slope (m) of the line represented by this equation can be calculated using the formula:

\(m = -\frac{A}{B}\)

Applying the Formula to the Given Equation

The given equation of the line is:

\(4x + 3y - 4 = 0\)

Comparing this equation with the standard form \(Ax + By + C = 0\), we can identify the coefficients A and B:

  • A is the coefficient of x, which is 4. So, \(A = 4\).
  • B is the coefficient of y, which is 3. So, \(B = 3\).
  • C is the constant term, which is -4. So, \(C = -4\). (Note: C is not needed to find the slope using this formula).

Now, we use the slope formula \(m = -\frac{A}{B}\):

\(m = -\frac{4}{3}\)

Calculating the Slope

Substituting the values of A and B into the formula, we get:

Slope \(m = -\frac{4}{3}\)

Thus, the slope of the line \(4x + 3y - 4 = 0\) is \(-\frac{4}{3}\).

Conclusion

The slope of the line \(4x + 3y - 4 = 0\) is \(-\frac{4}{3}\).

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Important Questions from Properties of Lines

  1. Let x + 2y + 4 = 0 and -4x + 2y - 3 = 0 be the equations of two straight lines. Then

  2. If the slope of the line joining the points (k, 4) and (-3, -2) is \(\frac{1}{2}\), then the value of k is

  3. If the equation

    3x2 + 7xy + 2y2 + 5x + 5y + k = 0

    represents a pair of straight lines, then the value of k is

  4. If the sum of the slopes of the lines given by x2 - 2cxy - 7y2 = 0 is four time their products, then the value of c is

  5. The foot of the perpendicular from the point (2, 4) upon x + y = 1 is

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