The problem describes a right triangle with side lengths given in terms of '$x$': $(x – 13)$ cm, $(x – 26)$ cm, and $x$ cm. In a right triangle, the longest side is the hypotenuse, and the other two sides are the legs (base and height). Since $x$ is the largest value among the three expressions (assuming $x > 26$), $x$ represents the hypotenuse. The other two sides, $(x – 13)$ and $(x – 26)$, are the legs of the right triangle.
The Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides (legs). We can write this relationship as:
$$ (\text{leg}_1)^2 + (\text{leg}_2)^2 = (\text{hypotenuse})^2 $$
Substituting the given side lengths:
$$ (x – 13)^2 + (x – 26)^2 = x^2 $$
Now, we need to solve this equation for $x$. First, expand the squared terms:
Substitute these expanded forms back into the equation:
$$ (x^2 - 26x + 169) + (x^2 - 52x + 676) = x^2 $$
Combine like terms on the left side:
$$ 2x^2 - 78x + 845 = x^2 $$
Rearrange the equation to form a standard quadratic equation ($ax^2 + bx + c = 0$):
$$ 2x^2 - x^2 - 78x + 845 = 0 $$
$$ x^2 - 78x + 845 = 0 $$
We can solve this quadratic equation by factoring. We need two numbers that multiply to 845 and add up to -78. These numbers are -13 and -65.
So, the equation factors as:
$$ (x – 13)(x – 65) = 0 $$
This gives two possible solutions for $x$:
We must check if these values of $x$ result in valid side lengths for a triangle (all sides must be positive).
The area of a right triangle is calculated using the formula:
$$ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} $$
Using the lengths of the two legs ($39$ cm and $52$ cm):
$$ \text{Area} = \frac{1}{2} \times 39 \, \text{cm} \times 52 \, \text{cm} $$
$$ \text{Area} = 39 \, \text{cm} \times \frac{52}{2} \, \text{cm} $$
$$ \text{Area} = 39 \, \text{cm} \times 26 \, \text{cm} $$
$$ \text{Area} = 1014 \, \text{cm}^2 $$
The area of the right triangle is 1014 cm².
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