The problem asks us to find the ratio between the perimeter of a square and the perimeter of a rectangle, given their dimensions.
First, let's calculate the perimeter of the square.
The formula for the perimeter of a square is:
$ P_{square} = 4 \times side $
Given that the side of the square is $6$ cm:
$ P_{square} = 4 \times 6 \text{ cm} $
$ P_{square} = 24 \text{ cm} $
Next, we calculate the perimeter of the rectangle.
The formula for the perimeter of a rectangle is:
$ P_{rectangle} = 2 \times (length + breadth) $
The length of the rectangle is given as $10$ cm and the breadth is $4$ cm.
$ P_{rectangle} = 2 \times (10 \text{ cm} + 4 \text{ cm}) $
$ P_{rectangle} = 2 \times (14 \text{ cm}) $
$ P_{rectangle} = 28 \text{ cm} $
Finally, we need to find the ratio between the perimeter of the square and the perimeter of the rectangle.
The ratio is expressed as:
$ \text{Ratio} = \frac{P_{square}}{P_{rectangle}} $
Substituting the calculated values:
$ \text{Ratio} = \frac{24 \text{ cm}}{28 \text{ cm}} $
To simplify the ratio, we find the greatest common divisor (GCD) of $24$ and $28$, which is $4$. Divide both parts of the ratio by $4$:
$ \text{Ratio} = \frac{24 \div 4}{28 \div 4} = \frac{6}{7} $
So, the ratio between the perimeter of the square and the perimeter of the rectangle is $6:7$.
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