The side of a regular hexagon is 10 mm. What is the across flat to the flat of the hexagon?
17.32
The question asks us to find the distance across the flats of a regular hexagon when the length of its side is given as 10 mm.
Understanding Regular Hexagon Properties
A regular hexagon is a polygon with six equal sides and six equal interior angles. The distance 'across flats' refers to the shortest distance between two opposite parallel sides of the hexagon. This distance passes through the center of the hexagon.
Calculating the Distance Across Flats
To find the distance across flats, we can use a specific formula related to the side length ($s$) of the regular hexagon. A regular hexagon can be divided into six equilateral triangles, with each side of the triangle equal to the side length of the hexagon.
The distance from the center of the hexagon to the midpoint of a side is called the apothem ($a$). The apothem is the height of one of these equilateral triangles.
The formula for the apothem ($a$) of an equilateral triangle (and thus the apothem of the hexagon) with side length $s$ is:
$$a = \frac{s \sqrt{3}}{2}$$
The distance across flats is twice the apothem:
Distance across flats $= 2 \times a = 2 \times \left( \frac{s \sqrt{3}}{2} \right) = s \sqrt{3}$$
Step-by-Step Calculation
- Identify the given information: The side length ($s$) of the regular hexagon is 10 mm.
- Use the formula: The formula for the distance across flats is $s \sqrt{3}$.
- Substitute the side length: Substitute $s = 10$ mm into the formula. $$ \text{Distance across flats} = 10 \times \sqrt{3} $$
- Calculate the value: The approximate value of $\sqrt{3}$ is 1.732. $$ \text{Distance across flats} \approx 10 \times 1.732 $$
- Final Result: $$ \text{Distance across flats} \approx 17.32 \text{ mm} $$
Conclusion
Comparing the calculated distance with the given options, the value 17.32 mm matches option 1. Therefore, the distance across the flats of the regular hexagon is approximately 17.32 mm.
Important Questions from Miscellaneous
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A railway wagon (open at the top) of mass M1 is moving with speed v1 along a straight track. As a result of rain, after some time it gets partially filled with water so that the mass of the wagon becomes M2 and speed becomes v2. Taking the rain to be falling vertically and the water stationery inside the wagon, the relation between the two speeds v1 and v2 is :
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1. Distance between the longitudes becomes zero on North Pole and South Pole.
2. Distance between the longitudes is maximum on the Equator.
3. Number of longitudes is more than number of latitudes.
Which of the statements given above is/are correct?
One block of 2⋅0 kg mass is placed on top of another block of 3⋅0 kg mass. The coefficient of static friction between the two blocks is 0⋅2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10 m/s2, the maximum value of the frictional force is :
