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Question

The shape factor for a solid circular section of diameter D is equal to:

The correct answer is

16/3π

Understanding Shape Factor for Structural Sections

The shape factor is a fundamental property in structural analysis, particularly in plastic design. It is defined as the ratio of the plastic section modulus (\(Z_p\)) to the elastic section modulus (\(Z_e\)) of a structural section.

Shape Factor \(k = \frac{Z_p}{Z_e}\)

This factor indicates how much additional load a section can carry beyond the yield point before a plastic hinge forms, compared to the load at which the extreme fibers first yield. For symmetrical sections like a solid circle, the neutral axis for both elastic and plastic analysis is the centroidal axis.

Calculating Elastic Section Modulus (\(Z_e\)) for a Solid Circular Section

For a solid circular section of diameter \(D\), the moment of inertia (\(I\)) about its centroidal axis is given by:

\(I = \frac{\pi D^4}{64}\)

The distance from the neutral axis to the extreme fiber (\(y_{max}\)) is half the diameter:

\(y_{max} = \frac{D}{2}\)

The elastic section modulus (\(Z_e\)) is calculated as the ratio of the moment of inertia to the distance to the extreme fiber:

\(Z_e = \frac{I}{y_{max}} = \frac{\frac{\pi D^4}{64}}{\frac{D}{2}}\)

Simplifying the expression:

\(Z_e = \frac{\pi D^4}{64} \times \frac{2}{D} = \frac{2\pi D^4}{64D} = \frac{\pi D^3}{32}\)

Calculating Plastic Section Modulus (\(Z_p\)) for a Solid Circular Section

The plastic section modulus (\(Z_p\)) for a section is the sum of the first moments of the areas above and below the plastic neutral axis, about the plastic neutral axis. For a solid circle, the plastic neutral axis is the centroidal axis (the diameter).

Consider the solid circle divided into two semi-circles by the diameter (plastic neutral axis). Let \(R\) be the radius, so \(R = D/2\). The area of each semi-circle is \(A_{semi} = \frac{1}{2} \pi R^2 = \frac{1}{2} \pi (\frac{D}{2})^2 = \frac{\pi D^2}{8}\).

The centroid of a semi-circular area is located at a distance of \(\frac{4R}{3\pi}\) from the diameter. For a solid circle with radius \(R\), this distance is \(\frac{4(D/2)}{3\pi} = \frac{2D}{3\pi}\).

The first moment of area of one semi-circle about the diameter is \(A_{semi} \times \text{centroid distance}\):

\(Q_{semi} = \frac{\pi D^2}{8} \times \frac{2D}{3\pi} = \frac{2\pi D^3}{24\pi} = \frac{D^3}{12}\)

The plastic section modulus \(Z_p\) is the sum of the absolute first moments of area of the two semi-circles about the plastic neutral axis:

\(Z_p = Q_{upper} + Q_{lower} = \frac{D^3}{12} + \frac{D^3}{12} = \frac{2D^3}{12} = \frac{D^3}{6}\)

Alternatively, using the radius \(R=D/2\), the first moment of area of a semi-circle of radius \(R\) about its diameter is \(\frac{2R^3}{3}\).

\(Z_p = \frac{2R^3}{3} + \frac{2R^3}{3} = \frac{4R^3}{3}\)

Substituting \(R = D/2\):

\(Z_p = \frac{4(D/2)^3}{3} = \frac{4(D^3/8)}{3} = \frac{D^3/2}{3} = \frac{D^3}{6}\)

Both methods yield the same plastic section modulus:

\(Z_p = \frac{D^3}{6}\)

Calculating the Shape Factor

Now, we can calculate the shape factor using the formula \(k = \frac{Z_p}{Z_e}\):

\(k = \frac{\frac{D^3}{6}}{\frac{\pi D^3}{32}}\)

\(k = \frac{D^3}{6} \times \frac{32}{\pi D^3}\)

\(k = \frac{32}{6\pi}\)

Simplifying the fraction \(\frac{32}{6}\) by dividing the numerator and denominator by 2:

\(k = \frac{16}{3\pi}\)

Conclusion

The shape factor for a solid circular section of diameter \(D\) is \(\frac{16}{3\pi}\).

Let's compare this result with the given options:

  • Option 1: \(D/2\pi\)
  • Option 2: \(16/3\pi\)
  • Option 3: \(\pi D/8\)
  • Option 4: \(15/2\pi\)

The calculated shape factor matches Option 2.

Revision Table: Solid Circular Section Properties

Property Formula (Diameter \(D\)) Formula (Radius \(R\))
Area (\(A\)) \(\frac{\pi D^2}{4}\) \(\pi R^2\)
Moment of Inertia (\(I\)) \(\frac{\pi D^4}{64}\) \(\frac{\pi R^4}{4}\)
Elastic Section Modulus (\(Z_e\)) \(\frac{\pi D^3}{32}\) \(\frac{\pi R^3}{4}\)
Plastic Section Modulus (\(Z_p\)) \(\frac{D^3}{6}\) \(\frac{4R^3}{3}\)
Shape Factor (\(k\)) \(\frac{16}{3\pi}\) \(\frac{16}{3\pi}\)

Additional Information: Importance of Shape Factor

The shape factor quantifies the reserve strength of a section beyond yielding in bending. A higher shape factor indicates a greater ability of the section to redistribute stresses after yielding starts, allowing it to carry more load before the entire section becomes plastic (forms a plastic hinge).

For example:

  • Rectangular section: \(k = 1.5\)
  • Solid circular section: \(k = \frac{16}{3\pi} \approx 1.698\)
  • Thin-walled circular tube: \(k \approx 1.27\)
  • I-section (compact): \(k \approx 1.1 to 1.2\)

Different cross-sectional shapes have different shape factors. This property is crucial in plastic analysis and design of structures, allowing engineers to determine the ultimate load-carrying capacity based on the full plastic moment rather than the yield moment. Understanding the shape factor helps in selecting efficient structural shapes for specific applications.

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Important Questions from Plastic Analysis

  1. A triangular beam section having base width ‘b’ and height ‘d’ the section modulus for beam strength is

  2. In a steel beam, when the width to thickness ratio of the compression flange is sufficiently large, local buckling of compression flange may occur even before extreme fibre yields. Such sections are generally known as

  3. If the shape factor of a section is 1.5 and the factor of safety to be adopted in 2, then the load factor will be

  4. The plastic theory is generally used for

  5. In plastic method of analysis, the value of yield stress of the grade of steel shall not exceed.

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