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Question

The S.I. on a certain sum of money for 4 years at 4 percent per annum exceeds the C.I. on the same sum for 3 years at 5 percent per annum by Rs. 57. Find the approximate sum.

The correct answer is

Rs. 24000

Finding the Approximate Principal Sum using Simple and Compound Interest Difference

This problem asks us to find the approximate original sum of money (the principal) given the difference between the Simple Interest (SI) earned over a period and the Compound Interest (CI) earned over a different period on the same sum, but possibly at different rates.

Understanding Simple Interest (SI)

Simple Interest is calculated only on the principal amount. It does not compound, meaning interest earned in previous periods is not added to the principal for calculating interest in the next period.

The formula for Simple Interest is:

SI = $\frac{P \times R \times T}{100}$

  • P is the Principal sum.
  • R is the annual rate of interest.
  • T is the time period in years.

Understanding Compound Interest (CI)

Compound Interest is calculated on the principal amount and also on the accumulated interest from previous periods. This means the interest "compounds" over time.

The formula for the total amount (Principal + CI) after T years compounded annually is:

Amount = $P \left(1 + \frac{R}{100}\right)^T$

The Compound Interest is then:

CI = Amount - P = $P \left(1 + \frac{R}{100}\right)^T - P$

Applying the Formulas to the Problem

Let the principal sum be P.

Calculate Simple Interest (SI)

The SI is for 4 years at 4 percent per annum.

  • P = P
  • R = 4%
  • T = 4 years

SI = $\frac{P \times 4 \times 4}{100} = \frac{16P}{100} = 0.16P$

Calculate Compound Interest (CI)

The CI is for 3 years at 5 percent per annum.

  • P = P
  • R = 5%
  • T = 3 years

CI = $P \left(1 + \frac{5}{100}\right)^3 - P$

CI = $P \left(1 + 0.05\right)^3 - P$

CI = $P (1.05)^3 - P$

Calculate $(1.05)^3$:

  • $1.05 \times 1.05 = 1.1025$
  • $1.1025 \times 1.05 = 1.157625$

So, CI = $P (1.157625) - P = P (1.157625 - 1) = 0.157625P$

Setting up the Difference Equation

The problem states that the SI exceeds the CI by Rs. 57.

SI - CI = 57

Substitute the calculated values of SI and CI:

$0.16P - 0.157625P = 57$

Solving for the Principal (P)

Combine the terms involving P:

$(0.16 - 0.157625)P = 57$

$0.002375P = 57$

Now, solve for P:

$P = \frac{57}{0.002375}$

Let's perform the division:

$P \approx 24000$

The approximate sum is Rs. 24000.

Verification with Options

Let's quickly verify the options:

Option Value (Rs.) SI (4 yrs at 4%) CI (3 yrs at 5%) Difference (SI - CI)
1 30000 $0.16 \times 30000 = 4800$ $0.157625 \times 30000 = 4728.75$ $4800 - 4728.75 = 71.25$
2 16000 $0.16 \times 16000 = 2560$ $0.157625 \times 16000 = 2522$ $2560 - 2522 = 38$
3 20000 $0.16 \times 20000 = 3200$ $0.157625 \times 20000 = 3152.5$ $3200 - 3152.5 = 47.5$
4 24000 $0.16 \times 24000 = 3840$ $0.157625 \times 24000 = 3783$ $3840 - 3783 = 57$

The calculation with P = 24000 yields a difference of 57, matching the problem statement exactly. Therefore, the approximate sum is Rs. 24000.

Revision Table: Key Concepts

Concept Formula Description
Simple Interest (SI) $SI = \frac{P \times R \times T}{100}$ Interest calculated only on the principal.
Compound Interest (CI) $CI = P \left(1 + \frac{R}{100}\right)^T - P$ Interest calculated on principal plus accumulated interest.
Principal (P) - The initial sum of money.
Rate (R) - The annual percentage rate.
Time (T) - The duration in years.

Additional Information: Approximations in Math Problems

Some problems in mathematics, especially those involving compound interest over several periods, can result in complex calculations. When asked for an "approximate sum," this indicates that the final answer might be rounded or that intermediate calculations could involve some level of rounding.

In this specific problem, calculating $(1.05)^3$ yields a precise value of 1.157625. The difference $0.16 - 0.157625 = 0.002375$ is also precise. Dividing 57 by 0.002375 gives exactly 24000. So, in this case, the "approximate" sum is actually the exact value among the given options. However, in other problems, you might need to round your final calculated value to match the closest option provided.

Always read the question carefully to understand if an exact value or an approximation is required. If options are given, they can help guide your level of precision in calculations.

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Important Questions from Simple and Compound Both

  1. X took a loan of Rs.1400 with simple interest for as many years as the rate of interest. If he paid Rs.1210 as interest at the end of that period, what was the rate of interest?

  2. The simple and compound interest that can be earned in two years at the same rate on a certain sum is Rs. 1,000 and Rs. 1,040 respectively. What is the rate (percent per annum) of interest?

  3. Compound interest on a certain sum of money for 2 years at a rate of 'r' per cent per annum (compounding annually) is Rs. 8385. Simple interest on the same sum at the same rate for 2 years is Rs 7800. What is the value of r?

  4. The compound interest accrued on Rs. 18000 in two years is Rs. 2995.2. What will be the simple interest accrued at the same rate of interest for the same sum for three years?

  5. Sam lent a sum of money at simple interest which amounted to Rs. 9800 in four years and the interest that he earned was Rs. 2800. Had he lent it at compound interest compounded annually for the same time and at the same rate, what would be the amount at the end of four years?

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