The required mass of oxygen to convert 1 kg of carbon into \(\frac{11}{3}\) kg of CO 2 is
The question asks for the mass of oxygen required to react completely with 1 kg of carbon to produce \(\frac{11}{3}\) kg of carbon dioxide (\(\text{CO}_2\)). This is a stoichiometry problem based on the balanced chemical equation for the combustion of carbon.
Carbon reacts with oxygen to form carbon dioxide according to the following balanced chemical equation:
\( \text{C} + \text{O}_2 \rightarrow \text{CO}_2 \)
To understand the mass relationships in the reaction, we need the molar masses of carbon (C), oxygen (\(\text{O}_2\)), and carbon dioxide (\(\text{CO}_2\)).
The balanced equation tells us that 1 mole of carbon reacts with 1 mole of oxygen gas to produce 1 mole of carbon dioxide. Using the molar masses, we can find the mass ratio:
1 mole C (12 g) reacts with 1 mole \(\text{O}_2\) (32 g) to produce 1 mole \(\text{CO}_2\) (44 g).
The mass ratio of C : \(\text{O}_2\) : \(\text{CO}_2\) is 12 : 32 : 44.
This ratio can be simplified by dividing each number by 4:
\( \frac{12}{4} : \frac{32}{4} : \frac{44}{4} = 3 : 8 : 11 \)
This means that for every 3 parts by mass of carbon, 8 parts by mass of oxygen are required to produce 11 parts by mass of carbon dioxide.
We are given that 1 kg of carbon reacts to produce \(\frac{11}{3}\) kg of \(\text{CO}_2\). Let's verify if this fits the 3:11 carbon to carbon dioxide mass ratio:
This matches the given information, confirming the reaction proceeds as expected based on stoichiometry.
Now, we need to find the mass of oxygen required for 1 kg of carbon using the carbon to oxygen mass ratio, which is 3:8.
Therefore, the required mass of oxygen to convert 1 kg of carbon into \(\frac{11}{3}\) kg of \(\text{CO}_2\) is \(\frac{8}{3}\) kg.
| Substance | Mass Ratio | Mass for 1 kg Carbon |
|---|---|---|
| Carbon (C) | 3 | 1 kg (Given) |
| Oxygen (\(\text{O}_2\)) | 8 | \( \frac{8}{3} \) kg (Calculated) |
| Carbon Dioxide (\(\text{CO}_2\)) | 11 | \( \frac{11}{3} \) kg (Given) |
The calculation confirms that \(\frac{8}{3}\) kg of oxygen is needed.
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