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Question

The relationship between pressure (p) and depth of fluid (h) in the static condition is:

The correct answer is

p ∝ h

Understanding Pressure and Depth in Static Fluids

The question asks about the relationship between pressure (\(p\)) and the depth (\(h\)) of a fluid when the fluid is in a static condition (not moving). This is a fundamental concept in fluid mechanics, specifically hydrostatics.

The Formula for Pressure at Depth

In a static fluid, the pressure at a certain depth below the surface is given by the formula:

\(p = p_0 + \rho g h\)

Let's break down what each term means:

  • \(p\): The total pressure at the depth \(h\).
  • \(p_0\): The atmospheric pressure acting on the surface of the fluid.
  • \(\rho\): The density of the fluid.
  • \(g\): The acceleration due to gravity.
  • \(h\): The depth below the surface of the fluid.

Analyzing the Relationship

In the formula \(p = p_0 + \rho g h\), for a specific fluid at a given location, the atmospheric pressure (\(p_0\)), the fluid density (\(\rho\)), and the acceleration due to gravity (\(g\)) are essentially constant values. Therefore, the pressure \(p\) is linearly dependent on the depth \(h\).

If we consider the gauge pressure, which is the pressure relative to atmospheric pressure (\(p - p_0\)), the formula becomes:

\(p - p_0 = \rho g h\)

This clearly shows that the gauge pressure is directly proportional to the depth \(h\):

\(p - p_0 \propto h\)

Even when considering the total pressure \(p\), since \(p_0\), \(\rho\), and \(g\) are constants, the term \(\rho g h\) is the part of the pressure that increases with depth. This increase is directly proportional to \(h\).

Therefore, the relationship between pressure and depth in a static fluid is a direct proportionality when considering the pressure change from the surface or gauge pressure, and a linear relationship for the total pressure.

Comparing with Options

Let's look at the given options:

  1. \(p \propto h\): This indicates a direct proportionality between pressure and depth. This matches our analysis of the relationship \(p - p_0 \propto h\), and also reflects the primary way pressure increases with depth \(p\) in \(p = p_0 + \rho g h\).
  2. \(p \propto 1/h^2\): This indicates an inverse square relationship, which is incorrect for pressure in a static fluid.
  3. \(p \propto 1/h\): This indicates an inverse relationship, which is incorrect for pressure in a static fluid.
  4. \(p \propto h^2\): This indicates proportionality to the square of the depth, which is incorrect for pressure in a static fluid.

The option \(p \propto h\) best describes the core relationship: as depth increases, pressure increases proportionally (above the atmospheric pressure).

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Important Questions from Hydrostatic Law

  1. What is the water pressure on the sea bottom at a depth of 6500 m? The specific gravity of sea water is assumed to be 1.03.

  2. If barometric pressure on a mountain top is 735 mm of mercury, then the pressure (in N/m2) will be:  

  3. Which law states that the rate of increase of pressure in a vertical direction is equal to weight density of a fluid at a point?

  4. A beaker contains water up to a height of h/3. Find the location of centre of pressure.

  5. The specific weight W of ocean water changes according to the equation W = Wo + C√h. W0 = Specific weight of ocean water at free surface and C is a constant. The pressure as a function of depth h is given by

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