The ratio of volume to surface area of solid semi sphere is related to its radius through
A solid hemisphere is exactly half of a solid sphere. It consists of a curved surface and a flat circular base. The key dimension defining a hemisphere is its radius, denoted by \(r\), which is the distance from the center of the circular base to any point on its circumference, and also from the center to any point on the curved surface.
The volume of a three-dimensional object measures the amount of space it occupies. Since a solid hemisphere is half of a solid sphere, its volume is half the volume of a full sphere. The formula for the volume of a sphere is \(\frac{4}{3}\pi r^3\).
The surface area of a solid hemisphere refers to the total area of all its surfaces. For a solid hemisphere, this includes two parts:
Let's break down each component:
The question asks for the ratio of volume to surface area of the solid hemisphere. We will use the formulas derived above to calculate this ratio.
Now, let's simplify the expression:
From our calculation, the ratio of volume to surface area of a solid hemisphere is \(\frac{2r}{9}\). This means the ratio is directly proportional to the radius \(r\). The constant of proportionality, or the factor through which it is related to the radius, is \(\frac{2}{9}\).
Therefore, the relationship is \( \text{Ratio} = \left(\frac{2}{9}\right) \times \text{radius} \).
Here is a quick summary of the formulas used for a solid hemisphere with radius \(r\):
| Characteristic | Formula |
|---|---|
| Volume (\(V\)) | \(\frac{2}{3}\pi r^3\) |
| Total Surface Area (TSA) | \(3\pi r^2\) |
| Ratio of Volume to Surface Area (\(\frac{V}{\text{TSA}}\)) | \(\frac{2r}{9}\) |
The numerical factor that relates the ratio of volume to surface area to its radius is \(\frac{2}{9}\).
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