The ratio of the depth of the parabolic and rectangular portion block at the limiting state of collapse of a singly reinforced section is:
4 : 3
Understanding the behavior of a singly reinforced section at the limiting state of collapse is crucial in structural design. According to IS 456:2000, the stress distribution in the compression zone of concrete at the ultimate limit state is represented by a specific stress block diagram. This stress block consists of two distinct parts: a parabolic portion and a rectangular portion.
The Indian Standard Code of Practice for Plain and Reinforced Concrete (IS 456:2000) specifies the stress-strain relationship for concrete in compression at the ultimate limit state. Key aspects of this relationship are:
This idealized stress-strain curve translates into a specific stress block diagram for the analysis of the compressive force in concrete. Let \(x_u\) be the depth of the neutral axis from the extreme compression fiber.
To determine the individual depths of the parabolic portion and the rectangular portion within the stress block, we analyze the strain distribution across the concrete section. The strain distribution is assumed to be linear from the extreme compression fiber to the neutral axis.
Let:
Consider a linear strain distribution diagram. Using principles of similar triangles, we can find the depth from the extreme compression fiber where the strain is \(0.002\). Let this depth be \(d_R\).
From the strain diagram, the strain at any depth \(y\) from the extreme compression fiber is given by:
$$\epsilon_y = \frac{\epsilon_{max}}{x_u} (x_u - y)$$
We are interested in the depth \(d_R\) where \(\epsilon_y = 0.002\):
$$0.002 = \frac{0.0035}{x_u} (x_u - d_R)$$
Rearranging the terms to solve for \(d_R\):
$$\frac{0.002}{0.0035} = \frac{x_u - d_R}{x_u}$$
$$\frac{4}{7} = 1 - \frac{d_R}{x_u}$$
$$\frac{d_R}{x_u} = 1 - \frac{4}{7}$$
$$\frac{d_R}{x_u} = \frac{3}{7}$$
Therefore, the depth of the portion where the strain varies from \(0.0035\) to \(0.002\) is \(d_R = \frac{3}{7} x_u\). This is the depth of the rectangular portion of the stress block, as the stress is considered constant over this region.
The remaining depth up to the neutral axis will correspond to the parabolic portion of the stress block. Let this depth be \(d_P\).
$$d_P = x_u - d_R$$
$$d_P = x_u - \frac{3}{7} x_u$$
$$d_P = \frac{4}{7} x_u$$
So, the depth of the parabolic portion of the stress block is \(d_P = \frac{4}{7} x_u\).
The question asks for the ratio of the depth of the parabolic portion to the depth of the rectangular portion of the stress block.
$$\text{Ratio} = \frac{\text{Depth of Parabolic Portion}}{\text{Depth of Rectangular Portion}}$$
$$\text{Ratio} = \frac{d_P}{d_R}$$
$$\text{Ratio} = \frac{\frac{4}{7} x_u}{\frac{3}{7} x_u}$$
$$\text{Ratio} = \frac{4}{3}$$
Thus, the ratio of the depth of the parabolic portion block to the rectangular portion block at the limiting state of collapse of a singly reinforced section is \(4:3\).
For a simply supported beam or slab, the effective span is calculated as:
Which of the following is CORRECT for indeterminate beam condition?
A cantilever beam is one which is -
In case of deep beam or in thin webbed R.C.C members, the first crack formed is-
In case of web crippling, the dispersion of load from bearing plate takes place at: