The ratio of the ages of A and B 8 years ago was 2 : 3. Four years ago, the ratio of their ages was 5 : 7. What will be the ratio of their ages 8 years from now?
4 : 5
This problem involves finding the ratio of the ages of two individuals, A and B, at a specific point in the future, given information about the ratio of their ages at two different points in the past. We are given the ratio of their ages 8 years ago and 4 years ago. We need to use this information to find their current ages and then calculate the ratio of their ages 8 years from now.
Let's denote the current age of A as \(A_0\) years and the current age of B as \(B_0\) years.
According to the question:
This gives us the equation: \(\frac{A_0 - 8}{B_0 - 8} = \frac{2}{3}\)
Cross-multiplying, we get: \(3(A_0 - 8) = 2(B_0 - 8)\)
\(3A_0 - 24 = 2B_0 - 16\)
Rearranging gives our first linear equation: \(3A_0 - 2B_0 = 24 - 16 \implies 3A_0 - 2B_0 = 8\) (Equation 1)
This gives us the equation: \(\frac{A_0 - 4}{B_0 - 4} = \frac{5}{7}\)
Cross-multiplying, we get: \(7(A_0 - 4) = 5(B_0 - 4)\)
\(7A_0 - 28 = 5B_0 - 20\)
Rearranging gives our second linear equation: \(7A_0 - 5B_0 = 28 - 20 \implies 7A_0 - 5B_0 = 8\) (Equation 2)
Now we have a system of two linear equations with two variables, \(A_0\) and \(B_0\):
Equation 1: \(3A_0 - 2B_0 = 8\)
Equation 2: \(7A_0 - 5B_0 = 8\)
We can solve this system using methods like substitution or elimination. Let's use elimination:
\((15A_0 - 10B_0) - (14A_0 - 10B_0) = 40 - 16\)
\(15A_0 - 14A_0 - 10B_0 + 10B_0 = 24\)
\(A_0 = 24\)
\(3(24) - 2B_0 = 8\)
\(72 - 2B_0 = 8\)
\(72 - 8 = 2B_0\)
\(64 = 2B_0\)
\(B_0 = \frac{64}{2} = 32\)
So, the current age of A is 24 years, and the current age of B is 32 years.
We need to find the ratio of their ages 8 years from now.
The ratio of their ages 8 years from now is:
\(\frac{\text{Age of A in 8 years}}{\text{Age of B in 8 years}} = \frac{32}{40}\)
Simplifying the ratio:
\(\frac{32}{40} = \frac{8 \times 4}{8 \times 5} = \frac{4}{5}\)
The ratio of their ages 8 years from now will be 4 : 5.
| Time Period | Age of A | Age of B | Ratio (A : B) |
|---|---|---|---|
| 8 years ago | \(24 - 8 = 16\) | \(32 - 8 = 24\) | \(16 : 24 = 2 : 3\) (Matches question) |
| 4 years ago | \(24 - 4 = 20\) | \(32 - 4 = 28\) | \(20 : 28 = 5 : 7\) (Matches question) |
| Current Age | 24 | 32 | \(24 : 32 = 3 : 4\) |
| 8 years from now | \(24 + 8 = 32\) | \(32 + 8 = 40\) | \(32 : 40 = 4 : 5\) (Calculated Answer) |
| Concept | Explanation | Example |
|---|---|---|
| Representing Ages | If current age is \(C\), age \(x\) years ago is \(C-x\), age \(y\) years from now is \(C+y\). | Current age is 30. Age 5 yrs ago is 25. Age 10 yrs from now is 40. |
| Age Difference | The difference in age between two people remains constant over time. | If A is 5 years older than B now, A will be 5 years older than B in any year. |
| Ratio of Ages | The ratio of ages changes over time because the same number of years is added to or subtracted from different base ages. | Ratio of 10 and 20 is 1:2. After 5 years, ages are 15 and 25, ratio is 3:5 (changed). |
| Setting up Equations | Translate the ratio information into algebraic equations involving current ages (\(A_0, B_0\)). | Ratio \(\frac{A_0-8}{B_0-8} = \frac{2}{3}\) leads to a linear equation. |
Solving age problems often involves solving systems of linear equations. Here's a brief look at common methods:
Choosing the right method depends on the structure of the equations. For two equations with two variables, substitution or elimination are usually the most straightforward.
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