The ratio of specific charge of a proton and a α-particle is
2 : 1
The specific charge of a particle is defined as the ratio of its electric charge ($q$) to its mass ($m$). It is a fundamental property used to characterize charged particles.
The formula for specific charge is:
\(\text{Specific Charge} = \frac{q}{m}\)
We need to find the ratio of the specific charge of a proton to the specific charge of an alpha (\(\alpha\))-particle.
A proton is a fundamental particle found in the nucleus of an atom.
The specific charge of a proton is:
\(\left(\frac{q}{m}\right)_p = \frac{+e}{m_p}\)
An alpha (\(\alpha\))-particle is the nucleus of a Helium atom (\(^{4}_{2}\text{He}\)). It consists of 2 protons and 2 neutrons.
The specific charge of an alpha-particle is:
\(\left(\frac{q}{m}\right)_\alpha = \frac{+2e}{4m_p} = \frac{e}{2m_p}\)
We need to find the ratio of the specific charge of a proton to that of an alpha-particle, which is \(\frac{(q/m)_p}{(q/m)_\alpha}\).
Ratio = \(\frac{\frac{e}{m_p}}{\frac{e}{2m_p}}\)
To simplify the ratio, we can invert the denominator and multiply:
Ratio = \(\frac{e}{m_p} \times \frac{2m_p}{e}\)
Cancel out the common terms \(e\) and \(m_p\):
Ratio = \(\frac{\cancel{e}}{\cancel{m_p}} \times \frac{2\cancel{m_p}}{\cancel{e}}\)
Ratio = \(2\)
So the ratio of the specific charge of a proton and an alpha-particle is 2:1.
| Particle | Charge (\(q\)) | Mass (\(m\)) (approx) | Specific Charge (\(q/m\)) (approx) |
|---|---|---|---|
| Proton | \(+e\) | \(m_p\) | \(\frac{e}{m_p}\) |
| Alpha-particle | \(+2e\) | \(4m_p\) | \(\frac{2e}{4m_p} = \frac{e}{2m_p}\) |
Ratio \((q/m)_p : (q/m)_\alpha\) = \(\frac{e}{m_p} : \frac{e}{2m_p}\)
Multiply both sides by \(2m_p\) to clear the denominators:
\(\left(\frac{e}{m_p} \times 2m_p\right) : \left(\frac{e}{2m_p} \times 2m_p\right)\)
\(2e : e\)
Divide both sides by \(e\):
\(2 : 1\)
Thus, the ratio is 2:1.
| Property | Proton | Neutron | Electron | Alpha Particle (\(\alpha\)) |
|---|---|---|---|---|
| Symbol | \(p\) or \(p^+\) | \(n\) or \(n^0\) | \(e\) or \(e^-\) | \(\alpha\) or \(^{4}_{2}\text{He}^{2+}\) |
| Charge (relative to \(e\)) | \(+1\) | \(0\) | \(-1\) | \(+2\) |
| Mass (relative to \(m_p\)) | \(1\) | \(\approx 1\) | \(\approx \frac{1}{1836}\) | \(\approx 4\) |
| Specific Charge (relative) | \(\frac{+1}{1} = +1\) | \(0\) | \(\frac{-1}{1/1836} = -1836\) | \(\frac{+2}{4} = +0.5\) |
Specific charge is an important concept in physics, especially in fields like mass spectrometry and particle physics. It allows scientists to identify particles and study their behaviour in electric and magnetic fields.
If $M$ is the mass of water that rises in a capillary tube of radius $r$, then what would be the total mass of water that rises if a capillary tube of radius $r$ and another capillary tube of radius $2r$ are simultaneously placed in water, assuming identical liquid and material properties?
The diameter of an atom is
The ratio of radii of two nuclei having atomic mass numbers 27 and 8 respectively, will be:
A $Be^{3+}$ ion, initially in its second excited state, absorbs a photon of wavelength $601.6\text{ A}$. The radius of the ion in the resulting excited state in terms of Bohr radius $a_0$ will be (Take $hc = 12500\text{ eV-A}$)
Ionising ______ has/have sufficient energy to affect the atoms in living cell and thereby damage their genetic material.