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Question

The ratio of S-wave to P-wave velocities for zero Poisson's ratio value is

The correct answer is
$\sqrt{2}$

Understanding S-wave and P-wave Velocities

Seismic waves, such as P-waves (Primary waves) and S-waves (Secondary waves), are crucial for understanding Earth's structure. Their speeds, or velocities, are determined by the elastic properties (like stiffness and compressibility) and the density of the material they travel through. P-waves are compressional waves that travel faster, meaning they arrive first at seismic stations. S-waves are shear waves that travel slower and arrive later.

The Significance of Poisson's Ratio

Poisson's ratio, represented by the Greek symbol $\nu$ (nu), is a fundamental property in the study of elasticity. It quantifies the degree to which a material contracts laterally when it is stretched longitudinally (or expands laterally when compressed longitudinally). For most common materials, $\nu$ falls between 0 and 0.5.

A zero Poisson's ratio ($\nu = 0$) represents a special case. It signifies a material that does not exhibit lateral strain when subjected to axial stress. In theoretical physics, this condition simplifies certain calculations related to wave propagation and material behavior.

Relating Wave Velocities and Poisson's Ratio

In the field of seismology and material physics, the velocities of P-waves ($V_P$) and S-waves ($V_S$) are linked through the material's elastic moduli and Poisson's ratio. For an isotropic and homogeneous elastic medium, the relationship between the ratio of S-wave to P-wave velocities and Poisson's ratio is given by the following equation derived from elasticity theory:

$$ \left(\frac{V_S}{V_P}\right)^2 = \frac{1 - 2\nu}{2(1 - \nu)} $$

This formula is key to understanding how seismic wave speeds vary with material properties.

Calculating the Velocity Ratio at $\nu=0$

The question specifically asks for the ratio $\frac{V_S}{V_P}$ when Poisson's ratio is zero ($\nu = 0$). To find this, we substitute $\nu = 0$ into the formula derived above:

Starting with the formula:

$$ \left(\frac{V_S}{V_P}\right)^2 = \frac{1 - 2\nu}{2(1 - \nu)} $$

Substitute $\nu = 0$:

$$ \left(\frac{V_S}{V_P}\right)^2 = \frac{1 - 2(0)}{2(1 - 0)} $$

Now, simplify the expression step-by-step:

$$ \left(\frac{V_S}{V_P}\right)^2 = \frac{1 - 0}{2(1)} $$
$$ \left(\frac{V_S}{V_P}\right)^2 = \frac{1}{2} $$

Finally, to find the ratio $\frac{V_S}{V_P}$, we take the square root of both sides of the equation:

$$ \frac{V_S}{V_P} = \sqrt{\frac{1}{2}} $$
$$ \frac{V_S}{V_P} = \frac{1}{\sqrt{2}} $$

Thus, the ratio of S-wave to P-wave velocities for a zero Poisson's ratio value is $\frac{1}{\sqrt{2}}$.

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Important Questions from Seismic Waves

  1. Which one of the following seismic phases results from a P-wave turning within the crust?
  2. Which one of the following correctly describes the attenuation property of the Earth expressed in terms of quality factor ($Q$)?
  3. A weak P-wave diffraction is observed in the epicentral distance range of
  4. What is the reflection coefficient for a seismic wave incident at normal to the interface between the first and second layers characterized by densities 3 g/cc and 2.5 g/cc, and velocities 5 km/s and 4 km/s, respectively?
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