The ratio of number of male and female employees in a company was 5 ∶ 4. Some new males and females joined the company in the ratio 2 ∶ 3. The total number of employees become 1620 and the ratio of males to females become 68 ∶ 67. Initially what was the total number of employees in the company?
1080
This problem involves tracking the number of male and female employees in a company as it changes due to new hires. We are given initial and final ratios of male to female employees, as well as the ratio in which new employees joined and the final total number of employees. The goal is to find the initial total number of employees.
Let's break down the information given and represent the unknown quantities using variables:
Now we need to solve the system of equations to find the value of $x$, which will help us determine the initial total number of employees ($9x$).
From equation (2), we can cross-multiply:
$$ 67(5x + 2y) = 68(4x + 3y) $$
Distribute the numbers:
$$ 335x + 134y = 272x + 204y $$
Gather like terms (move all $x$ terms to one side and $y$ terms to the other):
$$ 335x - 272x = 204y - 134y $$
$$ 63x = 70y $$
We can simplify this equation by dividing both sides by the greatest common divisor of 63 and 70, which is 7:
$$ \frac{63x}{7} = \frac{70y}{7} $$
$$ 9x = 10y $$
This equation gives a relationship between $x$ and $y$. We need to find the initial total, which is $9x$. Notice that the equation directly relates $9x$ and $10y$. Let's use equation (1) along with this relationship.
From $9x = 10y$, we can express $10y$ as $9x$. Equation (1) is $9x + 5y = 1620$. We need to substitute $y$ in terms of $x$ (or $x$ in terms of $y$), or use the direct relationship. Let's express $y$ in terms of $x$: $y = \frac{9x}{10}$.
Substitute this expression for $y$ into equation (1):
$$ 9x + 5\left(\frac{9x}{10}\right) = 1620 $$
Simplify the term with $y$:
$$ 9x + \frac{45x}{10} = 1620 $$
$$ 9x + \frac{9x}{2} = 1620 $$
To eliminate the fraction, multiply the entire equation by 2:
$$ 2(9x) + 2\left(\frac{9x}{2}\right) = 2(1620) $$
$$ 18x + 9x = 3240 $$
Combine the $x$ terms:
$$ 27x = 3240 $$
Now, solve for $x$:
$$ x = \frac{3240}{27} $$
Performing the division:
$$ x = 120 $$
The question asks for the initial total number of employees, which is $9x$.
Initial total employees = $9 \times x = 9 \times 120$
$$ \text{Initial total employees} = 1080 $$
Let's check if our values satisfy the conditions:
The calculation is consistent with all given conditions. The initial total number of employees was 1080.
Based on the initial ratio of male and female employees (5:4), the ratio of new employees joining (2:3), the final total number of employees (1620), and the final ratio of males to females (68:67), the initial total number of employees in the company was 1080.
| Concept | Description | Application in this Problem |
|---|---|---|
| Ratio Representation | Express quantities in a given ratio using a common variable (e.g., 5:4 becomes 5x and 4x). | Initial males=5x, Initial females=4x. New males=2y, New females=3y. |
| Total from Ratio | The total quantity is the sum of the parts in the ratio times the common variable (e.g., for ratio a:b, total is (a+b) times the variable). | Initial total = (5+4)x = 9x. New total = (2+3)y = 5y. |
| Setting up Equations | Translate the problem's conditions (like total amounts or final ratios) into algebraic equations involving the variables. | Equation 1: $9x + 5y = 1620$. Equation 2: $\frac{5x + 2y}{4x + 3y} = \frac{68}{67}$. |
| Solving System of Equations | Use methods like substitution or elimination to find the values of the variables. | Used substitution after simplifying the ratio equation to find $x$. |
| Finding Required Value | Once variables are found, calculate the specific quantity asked for in the question. | Calculated initial total as $9x$. |
A ratio is a comparison of two or more quantities of the same kind, measured in the same unit. It shows how much of one quantity there is compared to another. Ratios can be written as $a:b$, $a/b$, or "a to b". Proportions are statements that two ratios are equal, like $\frac{a}{b} = \frac{c}{d}$. Solving ratio and proportion problems often involves setting up equations based on the given relationships.
In problems like this, where quantities change, it's important to distinguish between the initial amounts, the change amounts, and the final amounts. Representing these with different variables or expressions derived from the initial variables helps in setting up accurate equations.
When dealing with ratios of sums or differences of quantities (like the ratio of total males to total females after some joined), setting up a proportion and cross-multiplying is a standard method to derive a linear equation relating the variables.
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