Problem Analysis

The question asks for the number of boys in Section B, given that the ratio of boys to girls is the same in both Section A and Section B. We are provided with the number of boys and girls in Section A and the number of girls in Section B.

Given Information

• Section A: 36 boys, 24 girls.
• Section B: Unknown number of boys, 28 girls.
• Condition: Ratio of boys to girls is the same for both sections.

Step-by-Step Solution

1. Calculate the ratio of boys to girls in Section A:

   Ratio (A) = \(\frac{\text{Number of boys in A}}{\text{Number of girls in A}}\) = \(\frac{36}{24}\)

   Simplify the ratio: \(\frac{36}{24} = \frac{3 \times 12}{2 \times 12} = \frac{3}{2}\)

2. Set up the ratio for Section B:

   Let \(B_{boys}\) be the number of boys in Section B.

   Ratio (B) = \(\frac{\text{Number of boys in B}}{\text{Number of girls in B}}\) = \(\frac{B_{boys}}{28}\)

3. Equate the ratios from both sections:

   Since the ratio is the same: Ratio (A) = Ratio (B)

   \(\frac{3}{2} = \frac{B_{boys}}{28}\)

4. Solve for the number of boys in Section B (\(B_{boys}\)):

   Multiply both sides by 28: \(B_{boys} = \frac{3}{2} \times 28\)

   \(B_{boys} = 3 \times \frac{28}{2}\)

   \(B_{boys} = 3 \times 14\)

   \(B_{boys} = 42\)

Conclusion

There are 42 boys in Section B.