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Question

The rank of the matrix \(A = \left[ {\begin{array}{*{20}{c}} 1&1&2\\ 1&2&3\\ 0&{ - 1}&1 \end{array}} \right]\)

The correct answer is

3

Understanding the Rank of Matrix A

The rank of a matrix is a fundamental concept in linear algebra. It represents the maximum number of linearly independent rows or, equivalently, the maximum number of linearly independent columns in the matrix. Another way to think about it is the dimension of the vector space spanned by its columns (or rows).

Calculating the Rank of the Given Matrix

We are given the matrix:

$$A = \left[ {\begin{array}{ccc} 1 & 1 & 2 \\ 1 & 2 & 3 \\ 0 & -1 & 1 \end{array}} \right]$$

We can find the rank by transforming the matrix into its Row Echelon Form (REF) using elementary row operations. The rank will be the number of non-zero rows in the REF.

Step-by-Step Row Reduction

Let's perform row operations:

  1. Start with the matrix A: $$ \left[ {\begin{array}{ccc} 1 & 1 & 2 \\ 1 & 2 & 3 \\ 0 & -1 & 1 \end{array}} \right] $$
  2. Replace the second row ($R_2$) with $R_2 - R_1$. This operation aims to create a zero in the first column, second row. $$ R_2 \leftarrow R_2 - R_1 $$ $$ \left[ {\begin{array}{ccc} 1 & 1 & 2 \\ 1-1 & 2-1 & 3-2 \\ 0 & -1 & 1 \end{array}} \right] = \left[ {\begin{array}{ccc} 1 & 1 & 2 \\ 0 & 1 & 1 \\ 0 & -1 & 1 \end{array}} \right] $$
  3. Replace the third row ($R_3$) with $R_3 + R_2$. This operation aims to create a zero in the second column, third row. $$ R_3 \leftarrow R_3 + R_2 $$ $$ \left[ {\begin{array}{ccc} 1 & 1 & 2 \\ 0 & 1 & 1 \\ 0 + 0 & -1 + 1 & 1 + 1 \end{array}} \right] = \left[ {\begin{array}{ccc} 1 & 1 & 2 \\ 0 & 1 & 1 \\ 0 & 0 & 2 \end{array}} \right] $$

The matrix is now in Row Echelon Form.

Determining the Rank from Row Echelon Form

The resulting matrix in Row Echelon Form is:

$$ \left[ {\begin{array}{ccc} 1 & 1 & 2 \\ 0 & 1 & 1 \\ 0 & 0 & 2 \end{array}} \right] $$

We count the number of non-zero rows in this matrix. All three rows have non-zero elements.

  • Row 1: (1, 1, 2) - Non-zero
  • Row 2: (0, 1, 1) - Non-zero
  • Row 3: (0, 0, 2) - Non-zero

Since there are 3 non-zero rows, the rank of the matrix A is 3.

Alternative Check: Using the Determinant

For a square matrix, if its determinant is non-zero, its rank is equal to its order (number of rows/columns). Let's calculate the determinant of A:

$$ \det(A) = 1 \cdot \left| {\begin{array}{cc} 2 & 3 \\ -1 & 1 \end{array}} \right| - 1 \cdot \left| {\begin{array}{cc} 1 & 3 \\ 0 & 1 \end{array}} \right| + 2 \cdot \left| {\begin{array}{cc} 1 & 2 \\ 0 & -1 \end{array}} \right| $$ $$ \det(A) = 1 \cdot ( (2)(1) - (3)(-1) ) - 1 \cdot ( (1)(1) - (3)(0) ) + 2 \cdot ( (1)(-1) - (2)(0) ) $$ $$ \det(A) = 1 \cdot ( 2 + 3 ) - 1 \cdot ( 1 - 0 ) + 2 \cdot ( -1 - 0 ) $$ $$ \det(A) = 1 \cdot (5) - 1 \cdot (1) + 2 \cdot (-1) $$ $$ \det(A) = 5 - 1 - 2 $$ $$ \det(A) = 2 $$

Since the determinant is 2, which is not equal to 0, the rank of the 3x3 matrix A is 3.

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Important Questions from System of Linear Equations

  1. For what value of k, the system linear equation has no solution

    (3k + 1)x + 3y - 2 = 0

    (k2 + 1)x + (k - 2)y - 5 = 0

  2. The system of equations x + 2y = 13 and 3x + 6y = 9 has:

  3. A system of equations is said to be inconsistent if

  4. A (-3, 4), B (5, 4), C and D form a rectangle. If x - 4y + 7 = 0 is a diameter of circum circle of the rectangle ABCD then area of rectangle ABCD is

  5. If a2 + b2 = 41 and a.b = 20, then (a + b) ÷ (a – b) = ______.

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