The radius of curvature of the path of a charged particle in a uniform magnetic field is directly proportional to
momentum of the charged particle
Based on our analysis of the formula r = (p)/(qB), the radius of curvature is directly proportional to the momentum of the charged particle. Therefore, the radius of curvature of the path of a charged particle in a uniform magnetic field is directly proportional to the momentum of the charged particle.
Important Questions from Motion in a Magnetic Field
Which of the following is the correct expression for cyclotron frequency?
The radius of curvature of a charged particle's passage in a homogeneous magnetic field is proportional to:
What is the period of revolution T of charge - q1 if a particle of mass m carrying a charge - q1 starts moving around a fixed charge + q2 along a circular path of radius r?
A proton and an alpha particle moving with same kinetic energy enter in the region of uniform magnetic field perpendicular to it. The ratio of radii of their trajectories will be:
- A 2.0 m long metallic rod is rotated with an angular frequency of 100 rad/s about an axis normal to the rod and passing through its one end. A uniform magnetic field of 2.0 T exits parallel to the axis. The emf induced between the two ends of the rod is:
