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Question

The product of two complex numbers 1 + i and 2 - 5i is

The correct answer is

7 - 3i

Complex Numbers Product Calculation

Understanding how to find the product of two complex numbers is a fundamental concept in mathematics. This problem asks us to multiply two specific complex numbers: \(1 + i\) and \(2 - 5i\). Let's break down the process step by step to find their product.

Complex Number Definition and Structure

A complex number is a number that can be expressed in the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit, defined as \(i = \sqrt{-1}\). The term \(a\) is called the real part, and \(b\) is called the imaginary part.

  • The real part corresponds to the numbers on the standard number line.
  • The imaginary part involves the imaginary unit \(i\), where \(i^2 = -1\). This property is crucial for simplifying expressions during complex number multiplication.

Product of Complex Numbers: Method Explained

To find the product of two complex numbers, say \( (a + bi) \) and \( (c + di) \), we use a method similar to multiplying two binomials in algebra, often referred to as the FOIL method (First, Outer, Inner, Last).

The steps involved are:

  • Multiply the First terms of each binomial.
  • Multiply the Outer terms.
  • Multiply the Inner terms.
  • Multiply the Last terms.
  • Substitute \(i^2 = -1\) wherever it appears.
  • Combine the real parts and the imaginary parts separately to express the final product in the standard \(a + bi\) form.

Product Calculation for (1 + i) and (2 - 5i)

Let's apply the method to find the product of the given complex numbers, \( (1 + i) \) and \( (2 - 5i) \).

Let \(z_1 = 1 + i\) and \(z_2 = 2 - 5i\).

We want to calculate \(z_1 \times z_2\):

\( (1 + i)(2 - 5i) \)

Now, let's perform the multiplication using the FOIL method:

  1. First terms: \(1 \times 2 = 2\)
  2. Outer terms: \(1 \times (-5i) = -5i\)
  3. Inner terms: \(i \times 2 = 2i\)
  4. Last terms: \(i \times (-5i) = -5i^2\)

Combining these results, we get:

\( 2 - 5i + 2i - 5i^2 \)

Next, we substitute the value of \(i^2\), which is \(-1\):

\( 2 - 5i + 2i - 5(-1) \)

\( 2 - 5i + 2i + 5 \)

Finally, we group and combine the real parts and the imaginary parts:

  • Real parts: \(2 + 5 = 7\)
  • Imaginary parts: \(-5i + 2i = -3i\)

So, the product of the two complex numbers is:

\( 7 - 3i \)

This is the final complex number product in the standard \(a + bi\) form.

Summary of Complex Number Multiplication
Term 1 Term 2 Product Simplified Product
\(1\) \(2\) \(2\) \(2\)
\(1\) \(-5i\) \(-5i\) \(-5i\)
\(i\) \(2\) \(2i\) \(2i\)
\(i\) \(-5i\) \(-5i^2\) \(-5(-1) = 5\)
Total Product (Real + Imaginary) \( (2 + 5) + (-5i + 2i) = 7 - 3i \)

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Important Questions from Complex Variables

  1. \(\cos \frac{\pi}{3}+\frac{1}{2} \cos \frac{2 \pi}{3}\)\(\frac{1}{3} \cos \frac{3 \pi}{3} \ldots \infty\)  = will 
  2. Imaginary part of \(\cos ^{-1}\left(\frac{3-2 i}{3+2 i}\right)\) = ______ 

  3. If f(z) is analytic in a simply connected domain D, then for every closed path C in D:

  4. If z is a complex variable, the value of \(\mathop \smallint \limits_5^{3{\rm{i}}} \frac{{{\rm{dz}}}}{{\rm{z}}}\) is 

  5. The argument of the complex number \(\frac{{1 + i}}{{1 - i}},\) where \(i = \sqrt { - 1}\), is

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