The product of two complex numbers 1 + i and 2 - 5i is
7 - 3i
Understanding how to find the product of two complex numbers is a fundamental concept in mathematics. This problem asks us to multiply two specific complex numbers: \(1 + i\) and \(2 - 5i\). Let's break down the process step by step to find their product.
A complex number is a number that can be expressed in the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit, defined as \(i = \sqrt{-1}\). The term \(a\) is called the real part, and \(b\) is called the imaginary part.
To find the product of two complex numbers, say \( (a + bi) \) and \( (c + di) \), we use a method similar to multiplying two binomials in algebra, often referred to as the FOIL method (First, Outer, Inner, Last).
The steps involved are:
Let's apply the method to find the product of the given complex numbers, \( (1 + i) \) and \( (2 - 5i) \).
Let \(z_1 = 1 + i\) and \(z_2 = 2 - 5i\).
We want to calculate \(z_1 \times z_2\):
\( (1 + i)(2 - 5i) \)
Now, let's perform the multiplication using the FOIL method:
Combining these results, we get:
\( 2 - 5i + 2i - 5i^2 \)
Next, we substitute the value of \(i^2\), which is \(-1\):
\( 2 - 5i + 2i - 5(-1) \)
\( 2 - 5i + 2i + 5 \)
Finally, we group and combine the real parts and the imaginary parts:
So, the product of the two complex numbers is:
\( 7 - 3i \)
This is the final complex number product in the standard \(a + bi\) form.
| Term 1 | Term 2 | Product | Simplified Product |
|---|---|---|---|
| \(1\) | \(2\) | \(2\) | \(2\) |
| \(1\) | \(-5i\) | \(-5i\) | \(-5i\) |
| \(i\) | \(2\) | \(2i\) | \(2i\) |
| \(i\) | \(-5i\) | \(-5i^2\) | \(-5(-1) = 5\) |
| Total Product (Real + Imaginary) | \( (2 + 5) + (-5i + 2i) = 7 - 3i \) | ||
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