The probability of getting a total of 7 on two dice thrown together is:
6/36
Understanding probability involves identifying all possible outcomes and the specific outcomes that satisfy the condition we are interested in. In this question, we are rolling two standard six-sided dice and want to find the probability that the sum of the numbers shown on the two dice is 7.
When two dice are thrown together, the outcome is a pair of numbers, one from each die. Let's list the steps to find the probability:
Each die has 6 possible outcomes (1, 2, 3, 4, 5, 6). When rolling two dice, the total number of possible combinations is the product of the outcomes for each die.
Total outcomes = Outcomes on Die 1 $\times$ Outcomes on Die 2
Total outcomes = $6 \times 6 = 36$
These 36 outcomes form the sample space. We can represent them as pairs (Die 1 result, Die 2 result).
We need to find the pairs of outcomes from the 36 total possibilities where the sum of the two numbers is exactly 7. Let's list them:
Counting these favorable outcomes, we find there are 6 ways to get a sum of 7 when rolling two dice.
Here is a table illustrating all possible sums when rolling two dice, highlighting the sums of 7:
| Die 1 \ Die 2 | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|
| 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| 5 | 6 | 7 | 8 | 9 | 10 | 11 |
| 6 | 7 | 8 | 9 | 10 | 11 | 12 |
Now we use the probability formula:
Probability (Sum of 7) = (Number of outcomes with sum 7) / (Total number of possible outcomes)
Probability (Sum of 7) = 6 / 36
This fraction can be simplified, but the options are given in the form of x/36. So, the probability of getting a total of 7 on two dice thrown together is 6/36.
This matches option 1.
| Event | Favorable Outcomes | Number of Favorable Outcomes | Probability (out of 36) |
|---|---|---|---|
| Sum of 2 | (1,1) | 1 | 1/36 |
| Sum of 3 | (1,2), (2,1) | 2 | 2/36 |
| Sum of 4 | (1,3), (2,2), (3,1) | 3 | 3/36 |
| Sum of 5 | (1,4), (2,3), (3,2), (4,1) | 4 | 4/36 |
| Sum of 6 | (1,5), (2,4), (3,3), (4,2), (5,1) | 5 | 5/36 |
| Sum of 7 | (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) | 6 | 6/36 |
| Sum of 8 | (2,6), (3,5), (4,4), (5,3), (6,2) | 5 | 5/36 |
| Sum of 9 | (3,6), (4,5), (5,4), (6,3) | 4 | 4/36 |
| Sum of 10 | (4,6), (5,5), (6,4) | 3 | 3/36 |
| Sum of 11 | (5,6), (6,5) | 2 | 2/36 |
| Sum of 12 | (6,6) | 1 | 1/36 |
| Total | 36 | 36/36 = 1 |
Probability is a measure of the likelihood of an event occurring. It is calculated as:
$$P(\text{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$$
Key points about probability:
If moment generating function of continuous random variable X is \(\frac{λ}{λ-t}\) t < λ, then E(X 3) equals to:
If moment generating function of discrete random variable X is (q + pe t) n, then E(X 2) equal to
If A and B are mutually exclusive events such that P(A) P(B) > 0, then which option is correct?
Two random variables X and Y are said to be independent if:
From standard pack of 52 cards, 3 cards are drawn at random without replacement. The probability of drawing a king, a queen and a jack in order is