The primary reason behind identically zero magnetic field outside a coaxial cable is:
Force between magnetic elements
A coaxial cable is specifically engineered to transmit electrical signals efficiently while minimizing external electromagnetic interference and preventing the leakage of its own electromagnetic fields. It is structured with an inner conductor, typically a solid wire, surrounded by an insulating layer. This is then encased by an outer cylindrical conductor, often a braided shield, and finally, an outer insulating jacket.
The defining characteristic of current flow in a coaxial cable, especially relevant to its magnetic properties, is that the current in the inner conductor flows in one direction, and an equal magnitude of current flows in the opposite direction through the outer conductor (the shield). For instance, if a current of magnitude 'I' travels inwards along the central conductor, an identical current 'I' will flow outwards along the outer conductor.
Each current-carrying conductor generates a magnetic field around itself. The magnetic field lines from the current in the inner conductor form concentric circles around it. Similarly, the current in the outer conductor also produces a magnetic field. However, because the current in the outer conductor flows in the direction opposite to that of the inner conductor, the magnetic fields they produce outside the cable largely oppose each other.
To understand the magnetic field outside the entire coaxial cable, we consider a hypothetical closed loop (an Amperian loop) encircling the cable beyond its outer conductor. According to Ampere's Law, the line integral of the magnetic field around such a loop is directly proportional to the total current enclosed by that loop:
\(\oint \vec{B} \cdot d\vec{l} = \mu_0 I_{enclosed}\)
In the case of a coaxial cable, for any Amperian loop drawn completely outside the outer conductor, the total enclosed current (\(I_{enclosed}\)) is the sum of the current in the inner conductor and the current in the outer conductor. Since these currents are equal in magnitude but opposite in direction, their net sum is zero (\(I_{enclosed} = I_{inner} + I_{outer} = 0\)).
Therefore, if \(I_{enclosed} = 0\), Ampere's Law simplifies to:
\(\oint \vec{B} \cdot d\vec{l} = 0\)
This result implies that the magnetic field (\(\vec{B}\)) in the region outside the coaxial cable is identically zero. The fields generated by the inner and outer currents perfectly cancel each other out in the external space.
The primary reason behind the identically zero magnetic field outside a coaxial cable is directly related to the concept of "Force between magnetic elements". Magnetic fields are the fundamental medium through which magnetic forces are exerted between current-carrying conductors or magnetic materials. If a region has an identically zero magnetic field, it fundamentally means that there is no magnetic influence present in that region capable of exerting a magnetic force on any external magnetic elements (such as another wire carrying current, or a compass needle).
The ingenious design of the coaxial cable, with its equal and opposite currents, precisely aims to cancel out the magnetic fields in the external region. This complete cancellation ensures that there is no net magnetic field available to mediate or cause forces on any external magnetic elements or current-carrying components. In essence, the zero magnetic field *is* the condition that fundamentally eliminates any potential 'force between magnetic elements' originating from the cable's external influence, making this concept the ultimate explanation for why the field is identically zero outside. This design minimizes electromagnetic interference and ensures the signal remains confined within the cable.
Which of the following frequency bands fall under microwave frequency?
Microwave MB-Communication uses_________ amplifier to obtain large gain over wide bandwidth
The impact of rains on microwave communication is higher in
The correct sequence of sub-systems of Klystron amplifiers as they appear in the direction of flow of electron beam is
Assertion (A) : TWTA is a narrow band device and has a helical structure and it is used as amplifier and oscillator.
Reason (R) : In TWT, the electron beam travels through a slow-wave structure and speed of electron beam is \(\dfrac{1}{10}\) of the velocity of light.