The price earnings ratio for firms in a certain industry follows the normal distribution. A firm’s price-earnings ratio has a standardized value (Z) = 1.0 and it is included in the highest _____ of firms in the industry.
15.87%
The question asks us to determine the percentage of firms in a certain industry that have a price-earnings (P/E) ratio equal to or higher than a firm with a standardized value (Z-score) of 1.0. We are told that the P/E ratios follow a normal distribution.
In a normal distribution, a Z-score measures how many standard deviations an observation is away from the mean. A Z-score of 1.0 means the firm's P/E ratio is one standard deviation above the industry average P/E ratio.
The normal distribution is symmetric around its mean (which corresponds to a Z-score of 0). The total area under the normal distribution curve is 1, or 100%. This area represents the total probability or the total percentage of firms.
We need to find the percentage of firms that have a Z-score greater than or equal to 1.0. This corresponds to the area under the normal distribution curve to the right of Z = 1.0.
Key properties of the standard normal distribution (Z-distribution) are helpful here:
To find the area to the right of Z = 1.0, we can subtract the area between Z = 0 and Z = 1.0 from the total area to the right of Z = 0:
Area (Z > 1.0) = Area (Z > 0) - Area (0 < Z < 1.0)
Area (Z > 1.0) $\approx$ 50% - 34.13%
Area (Z > 1.0) $\approx$ 15.87%
Alternatively, using a standard Z-table, the cumulative area to the left of Z = 1.0 is approximately 0.8413 or 84.13%. The area to the right is then:
Area (Z > 1.0) = 1 - Cumulative Area (Z $\le$ 1.0)
Area (Z > 1.0) $\approx$ 1 - 0.8413
Area (Z > 1.0) $\approx$ 0.1587 or 15.87%
This 15.87% represents the proportion of firms with a P/E ratio that is one standard deviation or more above the mean P/E ratio. Since the question asks for the percentage of firms included in the highest percentage, this 15.87% is the correct value.
A firm with a Z-score of 1.0 for its price-earnings ratio is at a point where 15.87% of firms in the industry have a P/E ratio equal to or higher than this firm. Therefore, it is included in the highest 15.87% of firms.
| Z-score | Area between Mean (0) and Z | Cumulative Area to the Left of Z | Area to the Right of Z |
|---|---|---|---|
| 0.0 | 0.00% | 50.00% | 50.00% |
| 1.0 | 34.13% | 84.13% | 15.87% |
| 2.0 | 47.72% | 97.72% | 2.28% |
| 3.0 | 49.87% | 99.87% | 0.13% |
| Concept | Explanation | Relevance to Problem |
|---|---|---|
| Normal Distribution | A symmetric, bell-shaped probability distribution. Many natural and financial variables follow this distribution. | The firm's P/E ratio follows this distribution, allowing us to use Z-scores. |
| Z-score (Standardized Value) | Measures how many standard deviations an observation is from the mean. Calculated as $\frac{(X - \mu)}{\sigma}$. | Given as 1.0 for the firm's P/E ratio. |
| Area under the Curve | Represents probability or proportion/percentage. Total area is 1 (100%). | We need to find the area to the right of Z=1.0 to find the percentage of firms with higher P/E ratios. |
The normal distribution is widely used in finance to model the distribution of various variables like stock returns, asset prices, and financial ratios such as the price-earnings ratio. Understanding the normal distribution and Z-scores helps analysts:
For instance, knowing a firm's P/E ratio has a Z-score of 1.0 helps contextualize its valuation within the industry – it indicates the firm is valued higher than a significant portion of its peers, assuming the P/E ratios are normally distributed.
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Select the correct answer using the code given below: