The presence of lead can be detected by six drops of sulphuric acid in a glass of water, which will yield:
White precipitate
The question asks about the observation when six drops of sulfuric acid are added to a glass of water containing lead. This is a chemical test used to detect the presence of lead ions in a solution.
When sulfuric acid ($\text{H}_2\text{SO}_4$) is added to water containing lead ions ($\text{Pb}^{2+}$), a chemical reaction occurs. Sulphuric acid dissociates to produce hydrogen ions ($\text{H}^{+}$) and sulfate ions ($\text{SO}_4^{2-}$).
The lead ions present in the water react with the sulfate ions from the sulfuric acid to form lead sulfate ($\text{PbSO}_4$). The chemical equation for this reaction is:
$$ \text{Pb}^{2+}\text{(aq)} + \text{SO}_4^{2-}\text{(aq)} \rightarrow \text{PbSO}_4\text{(s)} $$
Lead sulfate ($\text{PbSO}_4$) is a compound that is generally insoluble in water. Because it is insoluble, it separates from the solution as a solid, which is called a precipitate.
Lead sulfate ($\text{PbSO}_4$) is a white solid. Therefore, when it precipitates out of the solution, it appears as a white solid suspended in the water. This suspension of fine solid particles makes the water cloudy or opaque, which is observed as a white precipitate.
Thus, the reaction between lead ions and sulfuric acid specifically produces white lead sulfate.
Therefore, the presence of lead detected by adding sulfuric acid to water will yield a white precipitate.
The primary waste water treatment is aimed at:
Zero hardness of water is achieved by
The process of killing pathogenic group of microorganisms in water is called:
What gram of hardness per m3 of zeolite can be exchanged by natural zeolite?
Which of the following samplings does NOT test the quality before or after the sampling?