The output impedance of a voltage series feedback is 10 Ω, If the gain of the basic amplifier is 100 and feedback fraction is 0.01, what is the output impedance without feedback?
20 Ω
This problem asks us to determine the output impedance of a basic amplifier without feedback, given its output impedance with voltage series feedback, the basic amplifier gain, and the feedback fraction. Understanding how feedback affects amplifier parameters, especially impedance, is fundamental in electronics.
Voltage series feedback is a type of negative feedback where the feedback signal is proportional to the output voltage and is applied in series with the input voltage. This configuration is known for several key effects on amplifier characteristics:
The reduction in output impedance is a desirable feature for voltage amplifiers, as it makes them behave more like an ideal voltage source (which has zero output impedance).
Let's list the known values from the problem statement:
We need to find the output impedance of the amplifier without feedback, which we denote as \(R_o\).
For a voltage series feedback amplifier, the relationship between the output impedance with feedback (\(R_{of}\)) and the output impedance without feedback (\(R_o\)) is given by the formula:
\[R_{of} = \frac{R_o}{1 + A\beta}\]
Where:
Our goal is to find \(R_o\). We can rearrange the formula to solve for \(R_o\):
\[R_o = R_{of} \times (1 + A\beta)\]
First, let's calculate the product of the basic amplifier gain and the feedback fraction:
\[A\beta = 100 \times 0.01\]
\[A\beta = 1\]
Next, we add 1 to the loop gain to find the feedback factor:
\[1 + A\beta = 1 + 1\]
\[1 + A\beta = 2\]
Finally, we substitute the values of \(R_{of}\) and the calculated feedback factor into the rearranged formula:
\[R_o = 10 \, \Omega \times 2\]
\[R_o = 20 \, \Omega\]
The output impedance of the basic amplifier without feedback is \(20 \, \Omega\). This calculation confirms that applying voltage series feedback indeed reduces the output impedance from its original value of \(20 \, \Omega\) to \(10 \, \Omega\), highlighting a key advantage of using this feedback configuration in amplifier design.
The effect of negative feedback is to increase the __________ of a series voltage negative feedback amplifier by a factor of (1 + A vβ).
Which of the following improvement is obtained in negative feedback amplifier?
Feedback in an amplifier always helps to ________
What is the effect of current shunt feedback in an amplifier?