The Octal equivalent of the binary number 1011101011 is:
1353
Converting a binary number to its octal equivalent is a fundamental concept in digital systems and computer science. Both binary (base-2) and octal (base-8) are positional number systems.
The key to converting binary to octal is recognizing that \(8 = 2^3\). This means that every group of three binary digits corresponds directly to one octal digit.
To convert a binary number to octal, follow these steps:
Let's apply these steps to the given binary number: \(1011101011\)
We start from the right:
\(1011101011\)
Grouping:
\(1 \ 011 \ 101 \ 011\)
The leftmost group is just \(1\). It has only one digit. We need to pad it with two leading zeros to make it a group of three:
\(001 \ 011 \ 101 \ 011\)
We convert each group:
Let's convert each group to octal:
Here is a quick reference table for converting 3-digit binary to octal:
| Binary (3-bit) | Decimal | Octal |
|---|---|---|
| 000 | 0 | 0 |
| 001 | 1 | 1 |
| 010 | 2 | 2 |
| 011 | 3 | 3 |
| 100 | 4 | 4 |
| 101 | 5 | 5 |
| 110 | 6 | 6 |
| 111 | 7 | 7 |
Using the table, we can see:
Putting the octal digits together from left to right, we get:
\(1353_8\)
Therefore, the octal equivalent of the binary number \(1011101011_2\) is \(1353_8\).
| Original Binary | Grouped & Padded | Octal Equivalent per Group | Final Octal |
|---|---|---|---|
| \(1011101011\) | \(001 \ 011 \ 101 \ 011\) | \(1 \ 3 \ 5 \ 3\) | \(1353\) |
Number systems are ways of representing numbers. Common ones include:
Conversions between binary, octal, and hexadecimal are straightforward because their bases are powers of 2.
Consider the following statements :
1. (25)! + 1 is divisible by 26
2. (6)! + 1 is divisible by 7
Which of the above statements is/are correct ?
If the sum S is divided by 8, what is the remainder ?
If the sum S is divided by 60, what is the remainder ?
Find the sum of squares of the greatest value and the smallest value of K in the number so that the number 45082K is divisible by 3.
How many composite numbers are there from 53 to 97 ?