The number of oxygen atoms bonded to each phosphorus centre in P4O6, and P4O10 respectively, are
3 and 4
Let's understand the structures of phosphorus oxides, specifically P4O6 and P4O10, to determine the number of oxygen atoms bonded to each phosphorus atom.
Both P4O6 and P4O10 have cage-like structures derived from a tetrahedral arrangement of phosphorus atoms.
So, in $\text{P}_4\text{O}_6$, each phosphorus centre is bonded to 3 oxygen atoms.
So, in $\text{P}_4\text{O}_{10}$, each phosphorus centre is bonded to a total of 3 bridging oxygen atoms + 1 terminal oxygen atom = 4 oxygen atoms.
Based on the structures:
The number of oxygen atoms bonded to each phosphorus centre in P4O6 and P4O10 respectively are 3 and 4.
Consider the following pairs of compounds.
(i) NH4Cl and FeO
(ii) H3N∙BF3 and BCl3
(iii) HSO3F and HF
The more acidic species in (i), (ii) and (iii) are, respectively
Which of the following has the lowest boiling point?
Choose the equilibria from the following that are NOT favoured to go to right:
(A) As2S5 + 5HgO ⇌ As2O5 + 5 HgS
(B) La2(CO3)3 + Bi2S3 ⇌ La2S3 + Bi2(CO3)3
(C) CdSO4 + CaS ⇌ CdS + CaSO4
(D) BeF2 + HgI2 ⇌ BeI2 + HgF2
The reaction of XeF6 with a limited amount of quartz gives compound A. Then on reaction with an equivalent amount of XeO3, A gives B. The products A and B are, respectively