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Question

The number of expected electronic transitions in [Cr(en)3]3+ and trans-[Cr(en)2F2]+ at 4 K is, respectively (en = ethylenediamine)

The correct answer is 3 and 6

Electronic Transitions in Chromium Complexes

This question asks about the expected number of electronic transitions in two different chromium(III) complexes: [Cr(en)3]3+ and trans-[Cr(en)2F2]+. Both complexes involve chromium in the +3 oxidation state (Cr3+). The electronic configuration of Cr3+ is d3.

The electronic transitions in transition metal complexes typically involve the movement of electrons between d orbitals, influenced by the surrounding ligands. These are known as d-d transitions. The number and nature of these transitions depend on the symmetry of the complex.

[Cr(en)3]3+ Complex

The [Cr(en)3]3+ complex is a tris(ethylenediamine)chromium(III) ion. Ethylenediamine (en) is a bidentate ligand, and with three such ligands, the complex forms a six-coordinate structure. This complex has octahedral (Oh) symmetry.

  • Chromium(III) is a d3 ion.
  • In an octahedral ligand field, the ground state term symbol for a d3 ion is 4A2g.
  • The spin-allowed electronic transitions (where the spin multiplicity does not change, ΔS = 0) from the ground state 4A2g are to the excited quartet states: 4T2g, 4T1g(F), and 4T1g(P).
  • These three transitions correspond to the three main absorption bands observed in the visible and UV spectrum of octahedral Cr(III) complexes.

So, for [Cr(en)3]3+, the number of expected spin-allowed electronic transitions is 3.

trans-[Cr(en)2F2]+ Complex

The trans-[Cr(en)2F2]+ complex has two ethylenediamine ligands and two fluoride ligands in a trans configuration. This is also a six-coordinate complex, but its symmetry is lower than octahedral. The point group for this complex is D2h.

  • Chromium(III) is still a d3 ion.
  • Lowering the symmetry from Oh to D2h causes the degeneracy of the electronic states to be lifted (split).
  • The ground state 4A2g in Oh symmetry transforms as 4B1g in D2h symmetry (based on correlation tables).
  • The excited quartet states from Oh symmetry also split in D2h:
    • The 4T2g state splits into three states in D2h: 4Ag, 4B2g, and 4B3g.
    • The 4T1g(F) state splits into three states in D2h: 4B1g, 4B2g, and 4B3g.
    • The 4T1g(P) state splits into three states in D2h: 4B1g, 4B2g, and 4B3g.

At very low temperatures, like 4 K, the resolution of the electronic spectrum improves, and the splitting of these bands becomes observable. The question asks for the number of "expected" electronic transitions, which likely refers to the number of distinct electronic states that can be accessed from the ground state via spin-allowed transitions, considering the splitting in the lower symmetry.

Considering the splitting of the first two spin-allowed Oh bands:

  • Transitions from the ground state 4B1g to the components of 4T2g (which are 4Ag, 4B2g, 4B3g) give 3 possible transitions.
  • Transitions from the ground state 4B1g to the components of 4T1g(F) (which are 4B1g, 4B2g, 4B3g) give another 3 possible transitions.

Summing the components from the first two spin-allowed Oh bands, we get 3 + 3 = 6 distinct electronic transitions that are expected to be observed at low temperature due to the lifting of degeneracy in D2h symmetry.

The third spin-allowed Oh band (from 4T1g(P)) would also split into 3 components, potentially leading to more transitions, but based on the provided options, the count for the second complex seems to include only the components derived from the first two Oh quartet terms.

Summary of Expected Transitions

Complex Symmetry Ground State Excited Quartet States Considered Number of Expected Spin-Allowed Transitions
[Cr(en)3]3+ Oh 4A2g 4T2g, 4T1g(F), 4T1g(P) 3
trans-[Cr(en)2F2]+ D2h 4B1g (from 4A2g) Components of 4T2g and 4T1g(F) 3 (from 4T2g split) + 3 (from 4T1g(F) split) = 6

Therefore, the number of expected electronic transitions in [Cr(en)3]3+ and trans-[Cr(en)2F2]+ at 4 K is 3 and 6, respectively.

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