The number of distinct integers \(n\) for which \(\log_{\left(\frac{1}{4}\right)}\left(n^{2}-7n+11\right)>0\), is
0
For a base between 0 and 1, \(\log_{b}y>0\) holds exactly when \(0<y<1\).
So we need \(0<n^{2}-7n+11<1\).
For an integer \(n\), \(n^{2}-7n+11\) is an integer, and no integer lies strictly between 0 and 1.
Check: \(n=2,5 \Rightarrow 1\) (log = 0, not > 0); \(n=3,4 \Rightarrow -1\) (log undefined).
So no integer \(n\) satisfies the inequality.
Hence, 0.
The number of district pairs of integers (x, y) satisfying the inequalities
x > y ≥ 3 and x + y < 14 is
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