The number of bits used to store a BCD digit is
4
The question asks about the number of bits required to store a single Binary-Coded Decimal (BCD) digit. Let's break down what BCD is and how it works.
Binary-Coded Decimal, or BCD, is a way to represent decimal numbers (0 through 9) using binary codes. Unlike standard binary representation, where a number like 12 would be represented as $1100_2$, BCD represents each decimal digit individually using a fixed number of bits.
In BCD, each decimal digit from 0 to 9 is encoded using its own 4-bit binary equivalent. This ensures that the binary pattern for each digit is easily recognizable.
Here's how the decimal digits 0 through 9 are represented in BCD:
| Decimal Digit | BCD (4-bit Binary) |
|---|---|
| 0 | $0000_2$ |
| 1 | $0001_2$ |
| 2 | $0010_2$ |
| 3 | $0011_2$ |
| 4 | $0100_2$ |
| 5 | $0101_2$ |
| 6 | $0110_2$ |
| 7 | $0111_2$ |
| 8 | $1000_2$ |
| 9 | $1001_2$ |
To represent 10 different decimal digits (0 to 9), we need at least 10 distinct binary patterns. Let's see how many patterns we can make with different numbers of bits:
Since BCD uses a 4-bit pattern for each decimal digit, and the highest value needed is 9 ($1001_2$), 4 bits are the standard and necessary amount.
Therefore, the number of bits used to store a single BCD digit is 4.
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A code in which each decimal digit is represented by a group of 4 binary bits is
What would be the gray code equal to the number 14?
BCD equivalent of (345)10 is: