The number 56890065 is completely divisible by only:
3
The problem requires determining which number completely divides 56890065 from the given options. To solve this, we need to apply divisibility rules.
Divisibility by 9: A number is divisible by 9 if the sum of its digits is divisible by 9. For 56890065, the sum of digits is 5+6+8+9+0+0+6+5 = 39. Since 39 is not divisible by 9, 56890065 is not divisible by 9.
Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits, 39, is divisible by 3 (39 ÷ 3 = 13). Therefore, 56890065 is divisible by 3.
Divisibility by 11 and 4: For 11, the rule is alternating sum of digits should be divisible by 11. Alternating sum: (5-6+8-9+0-0+6-5) = -1, which is not divisible by 11. For 4, the last two digits, 65, are not divisible by 4. Therefore, 56890065 is not divisible by both 11 and 4.
Divisibility by 6 and 7: A number is divisible by 6 if divisible by both 2 and 3. 56890065 is not divisible by 2 (it's odd). Also, no individual test needed for 7 as 56890065 is not divisible by 6. Combined divisible by 6 and 7 is not possible here.
Thus, 56890065 is completely divisible by 3.
Important Questions from Divisibility and Remainder
If the 8-digit number 888x53y4 is divisible by 72, then what is the value of (7x + 2y), for the maximum value of y?
If all positive divisors of 132 are arranged in descending order, then what digit will be at unit place of first divisor ?
If 3 2019 is divided by 10, then what is the remainder?
The number 3798125P369 is divisible by 7. What is the value of the digit P?
Consider all 3-digit numbers (without repetition of digits) obtained using three non-zero digits which are multiples of 3. Let S be their sum.
Which of the following is/are correct?
1. S is always divisible by 74.
2. S is always divisible by 9.
select the correct answer using the code given below:
