The natural product that gives a signal at δ 218 ppm in its 13C NMR spectrum is
camphor
Nuclear Magnetic Resonance (NMR) spectroscopy is a powerful tool used to determine the structure of organic molecules. 13C NMR specifically provides information about the carbon framework of a molecule. The position of a signal in a 13C NMR spectrum, known as the chemical shift (\(\delta\)), is highly dependent on the electronic environment of the carbon atom.
Different types of carbon atoms resonate at different chemical shifts. Carbonyl carbons (C=O) typically appear significantly downfield (at higher \(\delta\) values) compared to other carbon atoms like sp\(^3\) carbons (alkanes), sp\(^2\) carbons (alkenes, aromatics), or carbons attached to oxygen or halogens.
The question asks to identify which natural product shows a signal at \(\delta\) 218 ppm in its 13C NMR spectrum. A chemical shift value around 200 ppm or higher is characteristic of carbonyl carbons, especially those in ketones and aldehydes. A value as high as 218 ppm is quite downfield, strongly suggesting a ketone carbonyl carbon in a specific structural environment.
Let's examine the given options:
Based on the typical chemical shift ranges for different functional groups and the specific structures of the natural products, the signal at \(\delta\) 218 ppm is highly characteristic of the carbonyl carbon in camphor.
Therefore, camphor is the natural product that gives a signal at \(\delta\) 218 ppm in its 13C NMR spectrum.
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| Column P | Column Q | ||
| A. | Ethyl acetate | i. | Two singlets in 1H NMR |
| B. | 2-chloropentane | ii. | Peak intensity at M:(M+2) is 3:1 in EI-MS |
| C. | 1,2-dibromo-2-methylpropane | iii. | Absorption band at 1740 cm-1 in IR |
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