The problem requires finding the minimum number of masonry units (bricks) needed to construct a solid dry wall with given dimensions.
First, convert all dimensions to meters for consistency.
Calculate the volume of a single brick ($V_{brick}$):
$ V_{brick} = 0.2 \, \text{m} \times 0.1 \, \text{m} \times 0.1 \, \text{m} = 0.002 \, \text{m}^3 $
Calculate the total volume of the wall ($V_{wall}$):
$ V_{wall} = 3 \, \text{m} \times 2 \, \text{m} \times 0.20 \, \text{m} = 1.2 \, \text{m}^3 $
To find the minimum number of bricks required, divide the total wall volume by the volume of a single brick. This calculation assumes no wastage and no mortar joints, suitable for a dry wall.
Number of bricks $N$:
$ N = \frac{V_{wall}}{V_{brick}} $
$ N = \frac{1.2 \, \text{m}^3}{0.002 \, \text{m}^3} = 600 $
The minimum number of masonry units required is 600.