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Question

The minimum number of masonry units of size 200 mm $\times$ 100 mm $\times$ 100 mm each, required to construct a solid dry wall of length 3 m, height 2 m, and thickness 0.20 m, is _____________ (in integer).

Calculating Masonry Units for a Solid Wall

The problem requires finding the minimum number of masonry units (bricks) needed to construct a solid dry wall with given dimensions.

Unit and Wall Dimensions

  • Brick Dimensions: Length = 200 mm, Width = 100 mm, Height = 100 mm.
  • Wall Dimensions: Length = 3 m, Height = 2 m, Thickness = 0.20 m.

Volume Calculations

First, convert all dimensions to meters for consistency.

  • Brick Dimensions in meters: 0.2 m $\times$ 0.1 m $\times$ 0.1 m.
  • Wall Dimensions in meters: 3 m $\times$ 2 m $\times$ 0.20 m.

Calculate the volume of a single brick ($V_{brick}$):

$ V_{brick} = 0.2 \, \text{m} \times 0.1 \, \text{m} \times 0.1 \, \text{m} = 0.002 \, \text{m}^3 $

Calculate the total volume of the wall ($V_{wall}$):

$ V_{wall} = 3 \, \text{m} \times 2 \, \text{m} \times 0.20 \, \text{m} = 1.2 \, \text{m}^3 $

Number of Units Required

To find the minimum number of bricks required, divide the total wall volume by the volume of a single brick. This calculation assumes no wastage and no mortar joints, suitable for a dry wall.

Number of bricks $N$:

$ N = \frac{V_{wall}}{V_{brick}} $

$ N = \frac{1.2 \, \text{m}^3}{0.002 \, \text{m}^3} = 600 $

The minimum number of masonry units required is 600.

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