The question asks us to find the mean proportional between the numbers 0.06 and 6. The mean proportional, also known as the geometric mean, between two numbers '$a$' and '$b$' is a number '$x$' such that the ratio of '$a$' to '$x$' is the same as the ratio of '$x$' to '$b$'.
Mathematically, if '$x$' is the mean proportional between '$a$' and '$b$', it satisfies the proportion:
$$ \frac{a}{x} = \frac{x}{b} $$
Cross-multiplying gives us:
$$ x^2 = a \times b $$
Therefore, the mean proportional '$x$' can be found by taking the square root of the product of the two numbers:
$$ x = \sqrt{a \times b} $$
In this problem, we have:
Now, we substitute these values into the formula:
$$ x = \sqrt{0.06 \times 6} $$
First, calculate the product of 0.06 and 6:
$$ 0.06 \times 6 = 0.36 $$
Next, find the square root of the product:
$$ x = \sqrt{0.36} $$
The square root of 0.36 is 0.6:
$$ x = 0.6 $$
The calculated mean proportional between 0.06 and 6 is 0.6.
Comparing this result with the given options:
The calculated value, 0.6, matches Option 2.
What number must be added to each of the numbers 15, 9 and 5 so that the resulting numbers may be in a continued proportion ?
When x is subtracted from each of 43, 38, 11 and 10, then the numbers so obtained in this order are in proportion. What is the mean proportional between (11x + 3) and (9x - 2) ?
Find the mean proportional between 4 and 900.
If 22, x, 88 are in a continued proportion, find the value of x.
A. 24
B. 33
C. 44
D. 36
The arithmetic mean and geometric mean of two numbers are 7 and 2√10 respectively, then find the numbers.