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Question

The mean of a set of 10 numbers is M. By combining with it a second set of M numbers, the mean of the combined set becomes 10. What is the sum of the second set of numbers?

The correct answer is

100

Understanding Mean and Combined Sets

The mean of a set of numbers is calculated by dividing the sum of the numbers by the total count of numbers in the set. The formula for the mean ($\bar{x}$) is:

$$ \bar{x} = \frac{\text{Sum of numbers}}{\text{Number of elements}} $$

Mean of the First Set

We are given that the first set has 10 numbers, and its mean is M.

Let the sum of the first set be S1.

Using the mean formula:

$$ M = \frac{S_1}{10} $$

Multiplying both sides by 10, we find the sum of the first set:

$$ S_1 = 10 \times M = 10M $$

Information about the Second Set

The second set is combined with the first set. The number of elements in the second set is given as M.

Let the sum of the second set be S2. This is what we need to find.

Combined Set Analysis

When the two sets are combined:

  • The total number of elements in the combined set is the sum of the number of elements in each set: $10 + M$.
  • The total sum of the numbers in the combined set is the sum of the sums of the individual sets: $S_1 + S_2 = 10M + S_2$.

We are also given that the mean of the combined set is 10.

Calculating the Sum of the Second Set

Using the mean formula for the combined set:

$$ \text{Mean of combined set} = \frac{\text{Sum of combined set}}{\text{Total number of elements}} $$

Substitute the known values:

$$ 10 = \frac{10M + S_2}{10 + M} $$

Now, we need to solve this equation for S2.

Multiply both sides by $(10 + M)$:

$$ 10 \times (10 + M) = 10M + S_2 $$

Distribute the 10 on the left side:

$$ (10 \times 10) + (10 \times M) = 10M + S_2 $$

$$ 100 + 10M = 10M + S_2 $$

To isolate S2, subtract 10M from both sides of the equation:

$$ 100 + 10M - 10M = 10M + S_2 - 10M $$

$$ 100 = S_2 $$

So, the sum of the second set of numbers is 100.

Final Answer Check

We found that the sum of the second set is 100. Let's quickly check if this makes sense in the equation:

$$ 10 = \frac{10M + 100}{10 + M} $$

$$ 10(10 + M) = 10M + 100 $$

$$ 100 + 10M = 10M + 100 $$

This equation is true, confirming our calculation for S2 is correct.

The sum of the second set of numbers is 100.

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Important Questions from Miscellaneous

  1. A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m/s. It hits the ground at a distance R from the building. Taking g = 10 m/s2 and neglecting air resistance will give :

  2. A sphere of volume V is made of a material with lower density than water. While on Earth, it floats on water with its volume f1V (f1 < 1) submerged. On the other hand, on a spaceship accelerating with acceleration a < g (g is the acceleration due to gravity on Earth) in outer space, its submerged volume in water is f2V. Then:

  3. A railway wagon (open at the top) of mass M1 is moving with speed v1 along a straight track. As a result of rain, after some time it gets partially filled with water so that the mass of the wagon becomes M2 and speed becomes v2. Taking the rain to be falling vertically and the water stationery inside the wagon, the relation between the two speeds v1 and v2 is :

  4. Consider the following statements:

    1. Distance between the longitudes becomes zero on North Pole and South Pole.

    2. Distance between the longitudes is maximum on the Equator.

    3. Number of longitudes is more than number of latitudes.

    Which of the statements given above is/are correct?

  5. One block of 2⋅0 kg mass is placed on top of another block of 3⋅0 kg mass. The coefficient of static friction between the two blocks is 0⋅2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10 m/s2, the maximum value of the frictional force is :

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