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Question

The maximum shear stress in a circular beam is

The correct answer is

1.33 times the average

Analyzing Maximum Shear Stress in Circular Beams

This explanation clarifies the calculation and concept behind the maximum shear stress within a circular beam, comparing it to the average shear stress.

Understanding Shear Stress in Beams

When a beam experiences a shear force ($V$), internal shear stresses are generated across its cross-section. The way these stresses distribute depends significantly on the shape of the beam's cross-section. For different shapes, the stress is not uniform.

Shear Stress Pattern in Circular Sections

In a beam with a circular cross-section, the shear stress distribution follows a parabolic pattern. Specifically:

  • The shear stress is minimal (zero) at the top and bottom points of the circle.
  • As you move from the edges towards the center (the neutral axis), the shear stress intensity increases.
  • The highest value, or maximum shear stress ($\tau_{max}$), is found precisely at the neutral axis, which is the centroidal axis of the circle.

Defining Average Shear Stress

The average shear stress ($\tau_{avg}$) is a simpler measure. It's calculated by taking the total shear force ($V$) applied to the cross-section and dividing it by the total area ($A$) of that cross-section.

The formula is:

$$ \tau_{avg} = \frac{V}{A} $$

This value represents the mean stress across the entire area, not the peak stress.

Calculating the Maximum Shear Stress for a Circular Beam

For a circular cross-section, the shear stress distribution is not uniform. Engineering mechanics provides a formula to calculate the maximum shear stress ($\tau_{max}$) based on the shear force ($V$) and the cross-sectional area ($A$). This maximum stress occurs at the neutral axis.

The formula is:

$$ \tau_{max} = \frac{4V}{3A} $$

Finding the Ratio: Maximum vs. Average Shear Stress

To determine how the maximum shear stress relates to the average shear stress, we can compute their ratio:

$$ \frac{\tau_{max}}{\tau_{avg}} = \frac{\frac{4V}{3A}}{\frac{V}{A}} $$

By simplifying this fraction, we cancel out $V$ and $A$:

$$ \frac{\tau_{max}}{\tau_{avg}} = \frac{4}{3} $$

When we convert the fraction $\frac{4}{3}$ into a decimal:

$$ \frac{4}{3} \approx 1.333... $$

Therefore, the maximum shear stress in a circular beam is approximately 1.33 times the average shear stress.

Evaluating the Options

Let's compare our result with the provided options:

Option Number Statement
1 1.25 times the average
2 1.33 times the average
3 1.50 times the average
4 2.00 times the average

Our calculation shows that $\tau_{max}$ is approximately 1.33 times $\tau_{avg}$, which directly corresponds to Option 2.

Final Conclusion

The stress distribution in a circular beam leads to a maximum shear stress value that is about 1.33 times the average shear stress calculated simply as shear force divided by area.

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Important Questions from Shear Stress and Bending Stress

  1. For a beam to be classified as a beam of uniform strength, which of the following conditions must be met?
  2. An increase in load at the free end of a cantilever is likely to cause failure-

  3. The maximum bending stress in a curved beam having symmetrical section always occurs at the

  4. The stresses caused by the bending moment is called -

  5. The bending moment at a section of a beam will have its local maximum where the shear force is-

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