The maximum demand of a consumer is 2 kW and his daily energy consumption is 24 units. His load factor is ______.
50%
The question asks us to calculate the load factor for a consumer given their maximum demand and daily energy consumption. The load factor is a crucial metric in electrical power systems that indicates how consistently a consumer uses electricity over a period compared to their maximum usage capacity.
It is defined as the ratio of the total energy consumed over a specific period to the maximum possible energy that could have been consumed if the maximum demand was maintained throughout that period. Mathematically, it can be expressed using the following formula:
Load Factor = $\frac{\text{Actual Energy Consumed over a Period}}{\text{Maximum Demand} \times \text{Total Hours in the Period}} \times 100\%$
Alternatively, it can also be expressed as:
Load Factor = $\frac{\text{Average Load}}{\text{Maximum Demand}} \times 100\%$
Where Average Load = $\frac{\text{Actual Energy Consumed over a Period}}{\text{Total Hours in the Period}}$.
We are provided with the following information:
In electrical terms, one 'unit' of energy is equivalent to one kilowatt-hour (kWh). So, the daily energy consumption is 24 kWh.
The period is daily, which means the total number of hours in the period is 24 hours.
Now, let's use the formula to calculate the load factor:
Load Factor = $\frac{\text{Daily Energy Consumption}}{\text{Maximum Demand} \times \text{Total Hours in a Day}} \times 100\%$
Substitute the given values into the formula:
Load Factor = $\frac{24 \text{ kWh}}{2 \text{ kW} \times 24 \text{ hours}} \times 100\%$
First, calculate the denominator:
Maximum possible energy consumption = $2 \text{ kW} \times 24 \text{ hours} = 48 \text{ kWh}$
Now, complete the load factor calculation:
Load Factor = $\frac{24 \text{ kWh}}{48 \text{ kWh}} \times 100\%$
Load Factor = $0.5 \times 100\%$
Load Factor = $50\%$
The calculated load factor is 50%. This means that, on average, the consumer utilized 50% of their maximum demand capacity over the 24-hour period.
Let's compare our calculated load factor with the given options:
Our calculated value of 50% matches Option 2.
| Parameter | Value |
|---|---|
| Maximum Demand | 2 kW |
| Daily Energy Consumption | 24 units (kWh) |
| Period Duration | 24 hours |
| Maximum Possible Consumption | 48 kWh |
| Load Factor | 50% |
| Term | Definition | Formula Example |
|---|---|---|
| Maximum Demand | The highest demand placed on the power system by a consumer during a specified period. Measured in kW or MW. | Given in question. |
| Energy Consumption | Total electrical energy used by a consumer over a period. Measured in kWh or MWh. | Given in question (24 units = 24 kWh). |
| Load Factor | Ratio of average load to maximum demand over a period, indicating utilization efficiency. | $\frac{\text{Energy Consumption}}{\text{Max Demand} \times \text{Hours}} \times 100\%$ |
| Average Load | Total energy consumed divided by the total hours in the period. | $\frac{\text{Energy Consumption}}{\text{Hours}}$ |
The load factor is important for several reasons:
A load factor of 100% represents a theoretical ideal where the maximum demand is maintained constantly throughout the period. In reality, load factors are always less than 100% because demand fluctuates.
Which of the following devices is suitable for the removal of gaseous pollutants?
The connected load of a consumer is 3 kW and his maximum demand is 1.5 kW. The demand factor of the consumer is
The decrease in the value of the power plant / electrical equipment and building due to constant use is known as:
Which component of the total cost of electrical energy is proportional to the energy generated (kWh)?
In electrical energy which type of tariff is also called as Doherty rate?